Suppose that a website contains two tables, the Customers table and the Orders table. Write a SQL query to find all customers who never order anything. Table: Customers. +----+-------+ | Id | Name | +----+-------+ | 1 | Joe | | 2 | Henry | | 3 | Sam | | 4 | Max | +----+-------+ Table: Orders. +----+------------+ | Id | CustomerId | +----+------------+ | 1 | 3 | | 2 | 1 | +----+------------+ Using the above tables as example, return the following: +-----------+ | Customers | +-----------+ | Henry | | Max | +-----------+ https://leetcode.com/problems/customers-who-never-order/description/ solution: 我想這個用用 left join 就好了吧 select Name as Customers from Customers c left join Orders o on c.Id = o.CustomerId where o.CustomerId is null; 要麼關聯要麼就子查詢 還能夠寫不少呀 SELECT Name as Customers FROM Customers c WHERE c.Id NOT IN (SELECT CustomerId FROM Orders o) ; SELECT Name as Customers FROM Customers c WHERE 0 = (SELECT count(1) tomerId FROM Orders o where c.Id = o.CustomerId) ; SELECT Name as Customers FROM Customers c WHERE NOT EXISTS (SELECT CustomerId FROM Orders o WHERE o.CustomerId = c.id) ;
git地址:https://github.com/woshiyexinjie/leetcode-xingit