Consecutive Available Seats --leetcode

Consecutive Available Seats
Several friends at a cinema ticket office would like to reserve consecutive available seats.
Can you help to query all the consecutive available seats order by the seat_id using the following cinema table?
| seat_id | free |
|---------|------|
| 1       | 1    |
| 2       | 0    |
| 3       | 1    |
| 4       | 1    |
| 5       | 1    |
Your query should return the following result for the sample case above.
| seat_id |
|---------|
| 3       |
| 4       |
| 5       |
Note:
The seat_id is an auto increment int, and free is bool ('1' means free, and '0' means occupied.).
Consecutive available seats are more than 2(inclusive) seats consecutively available.


solution:
select distinct a.seat_id
from cinema a join cinema b
  on abs(a.seat_id - b.seat_id) = 1
  and a.free = true and b.free = true
order by a.seat_id
;

note:
join
full join
inner join
right join
left join