1002. Find Common Characters

Given an array A of strings made only from lowercase letters, return a list of all characters that show up in all strings within the list (including duplicates). For example, if a character occurs 3 times in all strings but not 4 times, you need to include that character three times in the final answer.
You may return the answer in any order.
Example 1:

Input: ["bella","label","roller"]
Output: ["e","l","l"]

Example 2:

Input: ["cool","lock","cook"]
Output: ["c","o"]

Note:
1 <= A.length <= 100
1 <= A[i].length <= 100
Ai is a lowercase letter

難度: easy

題目：給定字符串數組Ａ僅由小字符組成，返回全部在全部字符串中都出現過的字符，包括重複。例如，若是一個字符在全部字符串出現了3次而非4次，則返回結果中要包含3次。返回順序不限。

思路：每一個字符串一個統計表。
Runtime: 7 ms, faster than 100.00% of Java online submissions for Find Common Characters.
Memory Usage: 38.1 MB, less than 100.00% of Java online submissions for Find Common Characters.

class Solution {
    public List<String> commonChars(String[] A) {
        int n = A.length;
        int[][] cc = new int[n][26];
        
        for (int i = 0; i < n; i++) {
            for (char c : A[i].toCharArray()) {
                cc[i][c - 'a']++;
            }
        }
        
        List<String> result = new ArrayList<>();
        for (int i = 0; i < 26; i++) {
            int minCount = 100;
            for (int j = 0; j < n; j++) {
                minCount = Math.min(minCount, cc[j][i]);
            }
            
            for (int j = 0; j < minCount; j++) {
                result.add(String.valueOf((char) (i + 'a')));
            }
        }
        
        return result;
    }
}