pandas經過字典生成dataframe

一、將一個字典輸入:spa

該字典必須知足:value是一個list類型的元素,且每個key對應的value長度都相同:code

(以該字典的key爲columns)blog

>>> import pandas as pd
>>> a = [1,2,3,4,5]
>>> b = ["a","b","c"]
>>> c = 1
>>> df = pd.DataFrame({"A":a,"B":b,"C":c})
Traceback (most recent call last):
ValueError: arrays must all be same length
>>> df = pd.DataFrame([a,b]) # 做爲list輸入,list的元素必須也是list,加入c就錯誤
>>> df
   0  1  2    3    4
0  1  2  3  4.0  5.0
1  a  b  c  NaN  NaN
# 統一一下字典每一個元素值的長度 >>> b = ["a","b","c","d","e"] >>> c = ("232","sdf","345","asd",1) >>> df = pd.DataFrame({"A":a,"B":b,"C":c}) >>> df A B C 0 1 a 232 1 2 b sdf 2 3 c 345 3 4 d asd 4 5 e 1

 

二、將多個key相同的字典列輸入:pandas

輸入爲一個list,該list各個元素爲dict,且key能夠不一樣(以含最多的key的字典的key爲columns):ast

>>> d1 = {"A":1,"B":2,"C":3}
>>> d2 = {"A":"a","B":"b",}
>>> d3 = {"A":(1,2),"B":"ab","C":3}
>>> li = [d1,d2,d3]
>>> df = pd.DataFrame(li)
>>> df
        A   B    C
0       1   2  3.0
1       a   b  NaN
2  (1, 2)  ab  3.0
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