最近接手一個項目中不少地方須要用到樹形結構表格等,所以本身封了個VUE的樹和表格組件,須要常常對兩種形式的數據進行相互轉換,這裏記錄下轉換的方法,組件等有時間再完善下也發上來。javascript
這個是最經常使用的,當咱們從後臺獲取一個扁平數組的時候,一般好比用id
、pid
來標識父子關係,如:java
var arr = [{id: 1, pid: '-1'},{id: 11, pid: '1'},{id: 12, pid: '1'}]
用map
記錄的方法是最經常使用效果也最好的複雜度是O(nlgn)
,支持多個根節點:node
function listToTree(list) { var map = {}, node, tree= [], i; for (i = 0; i < list.length; i ++) { map[list[i].id] = list[i]; list[i].children = []; } for (i = 0; i < list.length; i += 1) { node = list[i]; if (node.pid !== '-1') { map[node.pid].children.push(node); } else { tree.push(node); } } return tree; } listToTree(arr); //[{"id":1,"pid":"-1","children":[{"id":11,"pid":"1","children":[]},{"id":12,"pid":"1","children":[]}]}]
可是項目中有個需求,在後臺沒有返回給帶層級信息level
的時候,須要用到層級信息,這樣轉換無法計算出層級,所以就須要用迭代的方法了,默認根節點層級爲0,依次遞增:數組
function listToTreeWithLevel(list, parent, level) { var out = [] for (var node of list) { if (node.pid == parent) { node.level = level; var children = listToTreeWithLevel(list, node.id, level + 1) if (children.length) { node.children = children } out.push(node) } } return out } listToTreeWithLevel(arr, '-1', 0) //[{"id":1,"pid":"-1","children":[{"id":11,"pid":"1","children":[],"level":1},{"id":12,"pid":"1","children":[],"level":1}],"level":0}]
這個其實就是數據結構中的廣度優先遍歷:數據結構
function treeToList(tree) { var queen = []; var out = []; queen = queen.concat(tree); while(queen.length) { var first = queen.shift(); if (first.children) { queen = queen.concat(first.children) delete first['children']; } out.push(first); } return out; } var tree = [{"id":1,"pid":"-1","children":[{"id":11,"pid":"1","children":[]},{"id":12,"pid":"1","children":[]}]}]; treeToList(tree) //[{"id":1,"pid":"-1"},{"id":11,"pid":"1"},{"id":12,"pid":"1"}]