用python完成帶有進度條的圓周率計算

代碼如下： import math import time scale=14 s,m,=1,2 print("執行開始".center(scale//2, "-")) start = time.perf_counter() for i in range(scale+1): s=math.sqrt((1-math.sqrt(1-pow(s,2)))/2) m=m*2 a

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