C#中兩個List中根據指定條件--判斷並獲取不一樣數據的數據集合

C#中兩個List<TModel>中根據指定條件--判斷並獲取不一樣數據的數據集合

原始需求：已經插入的數據再也不重複插入(全部數據中排除已有數據，不存在數據以新對象形式存儲在對象三種)

方式一：

public class Test
    {
        public int age { get; set; }
        public string name { get; set; }
        public int score { get; set; }
    }

List<Test> list1 = new List<Test>();
            list1.Add(new Test { score = 10, name = "001" });
            list1.Add(new Test { score = 20, name = "002" });
            list1.Add(new Test { score = 30, name = "003" });
            list1.Add(new Test { score = 40, name = "004" });
            list1.Add(new Test { score = 50, name = "005" });
            list1.Add(new Test { score = 60, name = "005" });

            List<Test> list2 = new List<Test>();
            list2.Add(new Test { score = 10, name = "001" });
            list2.Add(new Test { score = 20, name = "002" });
            list2.Add(new Test { score = 30, name = "003" });
            list2.Add(new Test { score = 40, name = "004" });

            //list3 return 2
            List<Test> list3 = list1.Where(x => !list2.Any(x2 => x.score == x2.score)).ToList();
            //list4 return 2
            List<Test> list4 = list1.Where(x => list2.All(x2 => x.score != x2.score)).ToList();

            MessageBox.Show("list3==" + list3.Count+"\r\nlist4==" + list4.Count);

方式二：list一、list2數據參考方式一

public class DifferentModel : IEqualityComparer<Test>
    {
        public bool Equals(Test x, Test y)
        {
            return x.score == y.score;
        }

        public int GetHashCode(Test obj)
        {
            return obj.ToString().GetHashCode();
        }
    }

List<Test> different = list1.Except(list2, new DifferentModel()).ToList();//差集

MessageBox.Show("different=="+different.Count);

方式三：僅供參考，根據實際狀況注意Contains關鍵字 注意使用——不建議使用

//return 2

List<Test> temp = list1.Where(p => !list2.Select(b => b.score).Contains(p.score)).ToList();
MessageBox.Show("temp=="+temp.Count);