最近須要單獨使用到koa-compose這個模塊,雖然使用koa的時候大體知道中間件的執行流程,可是沒仔細研究過源碼用起來仍是不放心(主要是這個模塊代碼少,多的話也沒興趣去研究了)。閉包
koa-compose看起來代碼少,可是確實繞。閉包,遞歸,Promise。。。看了一遍腦子裏繞不清楚。看了網上幾篇解讀文章,都是針對單行代碼作解釋,仍是繞不清楚。最後只好採起一種傻瓜的方式:koa
koa-compose去掉一些註釋,類型校驗後,源碼以下:ui
function compose (middleware) {
return function (context, next) {
// last called middleware #
let index = -1
return dispatch(0)
function dispatch (i) {
if (i <= index) return Promise.reject(new Error('next() called multiple times'))
index = i
let fn = middleware[i]
if (i === middleware.length) fn = next
if (!fn) return Promise.resolve()
try {
return Promise.resolve(fn(context, dispatch.bind(null, i + 1)));
} catch (err) {
return Promise.reject(err)
}
}
}
}
複製代碼
寫出以下代碼:spa
var index = -1;
function compose() {
return dispatch(0)
}
function dispatch (i) {
if (i <= index) return Promise.reject(new Error('next() called multiple times'))
index = i
var fn = middleware[i]
if (i === middleware.length) fn = next
if (!fn) return Promise.resolve('fn is undefined')
try {
return Promise.resolve(fn(context, dispatch.bind(null, i + 1)));
} catch (err) {
return Promise.reject(err)
}
}
function f1(context,next){
console.log('middleware 1');
next().then(data=>console.log(data));
console.log('middleware 1');
return 'middleware 1 return';
}
function f2(context,next){
console.log('middleware 2');
next().then(data=>console.log(data));
console.log('middleware 2');
return 'middleware 2 return';
}
function f3(context,next){
console.log('middleware 3');
next().then(data=>console.log(data));
console.log('middleware 3');
return 'middleware 3 return';
}
var middleware=[
f1,f2,f3
]
var context={};
var next=function(context,next){
console.log('middleware 4');
next().then(data=>console.log(data));
console.log('middleware 4');
return 'middleware 4 return';
};
compose().then(data=>console.log(data));
複製代碼
直接運行結果以下:code
"middleware 1"中間件
"middleware 2"遞歸
"middleware 3"ip
"middleware 4"源碼
"middleware 4"string
"middleware 3"
"middleware 2"
"middleware 1"
"fn is undefined"
"middleware 4 return"
"middleware 3 return"
"middleware 2 return"
"middleware 1 return"
按着代碼運行流程一步步分析:
dispatch(0)
i==0,index==-1 i>index 往下
index=0
fn=f1
Promise.resolve(f1(context, dispatch.bind(null, 0 + 1)))
這就會執行
f1(context, dispatch.bind(null, 0 + 1))
進入到f1執行上下文
console.log('middleware 1');
輸出middleware 1
next()
其實就是調用
dispatch(1)
bind的功勞
遞歸開始
dispatch(1)
i==1,index==0 i>index 往下
index=1
fn=f2
Promise.resolve(f2(context, dispatch.bind(null, 1 + 1)))
這就會執行
f2(context, dispatch.bind(null, 1 + 1))
進入到f2執行上下文
console.log('middleware 2');
輸出middleware 2
next()
其實就是調用
dispatch(2)
接着遞歸
dispatch(2)
i==2,index==1 i>index 往下
index=2
fn=f3
Promise.resolve(f3(context, dispatch.bind(null, 2 + 1)))
這就會執行
f3(context, dispatch.bind(null, 2 + 1))
進入到f3執行上下文
console.log('middleware 3');
輸出middleware 3
next()
其實就是調用
dispatch(3)
接着遞歸
dispatch(3)
i==3,index==2 i>index 往下
index=3
i === middleware.length
fn=next
Promise.resolve(next(context, dispatch.bind(null, 3 + 1)))
這就會執行
next(context, dispatch.bind(null, 3 + 1))
進入到next執行上下文
console.log('middleware 4');
輸出middleware 4
next()
其實就是調用
dispatch(4)
接着遞歸
dispatch(4)
i==4,index==3 i>index 往下
index=4
fn=middleware[4]
fn=undefined
reuturn Promise.resolve('fn is undefined')
回到next執行上下文
console.log('middleware 4');
輸出middleware 4
return 'middleware 4 return'
Promise.resolve('middleware 4 return')
回到f3執行上下文
console.log('middleware 3');
輸出middleware 3
return 'middleware 3 return'
Promise.resolve('middleware 3 return')
回到f2執行上下文
console.log('middleware 2');
輸出middleware 2
return 'middleware 2 return'
Promise.resolve('middleware 2 return')
回到f1執行上下文
console.log('middleware 1');
輸出middleware 1
return 'middleware 1 return'
Promise.resolve('middleware 1 return')
回到全局上下文
至此已經輸出
"middleware 1"
"middleware 2"
"middleware 3"
"middleware 4"
"middleware 4"
"middleware 3"
"middleware 2"
"middleware 1"
那麼
"fn is undefined"
"middleware 4 return"
"middleware 3 return"
"middleware 2 return"
"middleware 1 return"
怎麼來的呢
回頭看一下,每一箇中間件裏都有
next().then(data=>console.log(data));
按照以前的分析,then裏最早拿到結果的應該是next中間件的,並且結果就是Promise.resolve('fn is undefined')
的結果,而後分別是f4,f3,f2,f1。那麼爲何都是最後才輸出呢?
Promise.resolve('fn is undefined').then(data=>console.log(data));
console.log('middleware 4');
複製代碼
運行一下就清楚了
或者
setTimeout(()=>console.log('fn is undefined'),0);
console.log('middleware 4');
複製代碼
整個調用過程還能夠當作是這樣的:
function composeDetail(){
return Promise.resolve(
f1(context,function(){
return Promise.resolve(
f2(context,function(){
return Promise.resolve(
f3(context,function(){
return Promise.resolve(
next(context,function(){
return Promise.resolve('fn is undefined')
})
)
})
)
})
)
})
)
}
composeDetail().then(data=>console.log(data));
複製代碼
方法雖蠢,可是compose的做用不言而喻了
最後,if (i <= index) return Promise.reject(new Error('next() called multiple times'))
這句代碼什麼時候回其做用呢?
一箇中間件裏調用兩次next()
,按照上面的套路走,相信很快就明白了。