[轉] json字符串轉換爲JSONObject和JSONArray

一.下載json 具體到http://www.json.org/上找java-json下載,並把其放到項目源代碼中,這樣就能夠引用其類對象了java

二.具體轉化過程json

//JSONObject數組

 String jsonMessage = "{\"語文\":\"88\",\"數學\":\"78\",\"計算機\":\"99\"}";
  String value1 = null;
  try
  {
   //將字符串轉換成jsonObject對象
   //JSONObject myJsonObject = new JSONObject(jsonMessage);(注:JSONObject.java源碼中無此構造方法)spa

 JSONObject myJsonObject = JSONObject.fromObject(jsonMessage);
   //獲取對應的值
   value1 = myJsonObject.getString("數學");
  }
  catch (JSONException e)
  {
  }
  
  System.out.println("value1="+value1);對象

//JSONArray字符串

jsonMessage = "[{'num':'成績', '外語':88, '歷史':65, '地理':99, 'object':{'aaa':'1111','bbb':'2222','cccc':'3333'}}," +
           "{'num':'興趣', '外語':28, '歷史':45, '地理':19, 'object':{'aaa':'11a11','bbb':'2222','cccc':'3333'}}," +
           "{'num':'愛好', '外語':48, '歷史':62, '地理':39, 'object':{'aaa':'11c11','bbb':'2222','cccc':'3333'}}]";
  JSONArray myJsonArray;
  try
  {
         //myJsonArray = new JSONArray(jsonMessage);(注:JSONArray.java源碼中無此構造方法)

    myJsonArray = JSONArray.fromObject(jsonMessage);get

   for(int i=0 ; i < myJsonArray.size() ;i++)
   {
    //獲取每個JsonObject對象
    JSONObject myjObject = myJsonArray.getJSONObject(i);
    
    //獲取每個對象中的值
    String numString = myjObject.getString("num");
    int englishScore = myjObject.getInt("外語");
    int historyScore = myjObject.getInt("歷史");
    int geographyScore = myjObject.getInt("地理");
    //獲取數組中對象的對象
    JSONObject myjObject2 = myjObject.getJSONObject("object");
    String aaaString = myjObject2.getString("aaa");
    System.out.println("aaaString="+aaaString);
    
    System.out.println("numString="+numString);
    System.out.println("englishScore="+englishScore);
    System.out.println("historyScore="+historyScore);
    System.out.println("geographyScore="+geographyScore);
   }
  }
  catch (JSONException e)
  {
  }
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