劍指offer——27. 二叉搜索樹與雙向鏈表（Java版）

題目:

 

劍指offer的題目有挺多都挺典型的，就像這一道。不過書中的代碼寫的真是ugly，有不少題目LeetCode上都有，能夠去LeetCode討論區看看，常常有一些大神分享，寫的代碼真是高效、簡潔、清晰，劍指offer上的代碼不只變量名定義又長又不知所云，讓人看着就很不清晰明瞭，還有各類不必的判斷讓代碼看起來很是不直觀。

思路：書中已經寫的挺清楚了，經過中序遍從來作。

package com.ss.offer;

/**
 * 2018-09-15 下午11:18.
 *
 * @author blank
 */
public class BST2LinkedList {
    public static void main(String[] args) throws Exception {
        BinaryTreeNode root = new BinaryTreeNode(10);
        BinaryTreeNode six = new BinaryTreeNode(6);
        BinaryTreeNode four = new BinaryTreeNode(4);
        BinaryTreeNode eight = new BinaryTreeNode(8);
        BinaryTreeNode fourteen = new BinaryTreeNode(14);
        BinaryTreeNode twelve = new BinaryTreeNode(12);
        BinaryTreeNode sixteen = new BinaryTreeNode(16);
        root.left = six;
        root.right = fourteen;
        six.left = four;
        six.right = eight;
        four.left = null;
        four.right = null;
        eight.left = null;
        eight.right = null;
        fourteen.left = twelve;
        fourteen.right = sixteen;
        twelve.left = null;
        twelve.right = null;
        sixteen.right = null;
        sixteen.left = null;
        BinaryTreeNode res = convert(root);
        while (res != null) {
            System.out.println(res.val);
            res = res.right;
        }
    }

    static BinaryTreeNode convert(BinaryTreeNode root) {

        BinaryTreeNode[] lastNode = new BinaryTreeNode[1];
        convertNode(root, lastNode);
        BinaryTreeNode headNode = lastNode[0];
        while (headNode.left != null)
            headNode = headNode.left;
        return headNode;

    }

    static void convertNode(BinaryTreeNode root, BinaryTreeNode[] last) {
        if (root == null) {
            return;
        }
        convertNode(root.left, last);
        if (last[0] != null) {
            last[0].right = root;
        }
        root.left = last[0];
        last[0] = root;
        convertNode(root.right, last);
    }

    private static class BinaryTreeNode {
        int val;
        BinaryTreeNode left;
        BinaryTreeNode right;

        public BinaryTreeNode(int val) {
            this.val = val;
        }
    }
}