線程間協做即有多個線程須要按照必定順序相互協做進行。主要有兩種方法來實現,使用鎖(互斥)來同步兩個任務的行爲。另外一種是使用BlockingQueue,它已經幫咱們處理好了同步機制,實現更加簡單。git
接下來以一個實際場景爲例,進行演示。假設在一個餐館中有一個服務員,有一個廚師,而服務員要等到廚子把菜作好了才能上菜,而後回來繼續等待。而廚師獲得新訂單後開始作菜。用兩種方式實現以前,咱們分析知廚師和服務員分別是一個獨立的線程,他們經過餐廳聯結在一塊兒。在這個模型中廚師表明生產者,服務員表明消費者。Order是他們共享的資源,須要進行同步。github
菜bash
public class Order {
private int num=0;
public Order(int num) {
this.num=num;
}
@Override
public String toString() {
return "order num:"+num;
}
}複製代碼
餐館ide
public class Restaurant {
Order order;
Chef chef=new Chef(this);
Waiter waiter=new Waiter(this);
ExecutorService executorService= Executors.newCachedThreadPool();
public Restaurant() {
order =null;
executorService.execute(chef);
executorService.execute(waiter);
try {
TimeUnit.SECONDS.sleep(5);
}catch (Exception e){
e.printStackTrace();
}
executorService.shutdown();
}
public static void main(String[] args){
new Restaurant();
}
}複製代碼
public class Chef implements Runnable {
private Restaurant restaurant;
private int counter=0;
public Chef(Restaurant restaurant) {
this.restaurant = restaurant;
}
@Override
public void run() {
try{
while (!Thread.interrupted()){
synchronized (this){
while (restaurant.meal!=null){
wait();//等服務員上菜,得到新訂單
}
}
synchronized (restaurant.waiter){
//得到服務員的鎖,讓他等我作菜
restaurant.meal=new Meal(counter++);
System.out.print("a meal is done");
Thread.sleep(500);
restaurant.waiter.notifyAll();
//告訴服務員能夠上菜了
}
}
}catch (Exception e){
e.printStackTrace();
}
}
}複製代碼
服務員ui
public class Waiter implements Runnable {
private Restaurant restaurant;
public Waiter(Restaurant restaurant) {
this.restaurant = restaurant;
}
@Override
public void run() {
try {
while (!Thread.interrupted()){
synchronized (this){
while (restaurant.order ==null){
wait();//等待廚師作完菜後被chef的notifyAll()喚醒,注意wait()會釋放當前得到的鎖
}
}
synchronized (restaurant.chef){
System.out.print("waiter: order up\n");
restaurant.order =null;
restaurant.chef.notifyAll();//告訴廚師能夠作菜了
}
}
}catch (Exception e){
e.printStackTrace();
}
}
}複製代碼
public class MealQueue extends LinkedBlockingQueue<Order> {
}複製代碼
餐館this
public class Restaurant {
private MealQueue waitQueue;
private MealQueue finishedQueue;
private Chef chef;
private Waiter waiter;
public Restaurant() {
waitQueue = new MealQueue();
finishedQueue = new MealQueue();
chef = new Chef(waitQueue, finishedQueue);
waiter = new Waiter(waitQueue, finishedQueue);
ExecutorService executorService = Executors.newCachedThreadPool();
executorService.execute(chef);
executorService.execute(waiter);
try {
Thread.sleep(5000);
} catch (InterruptedException e) {
e.printStackTrace();
}
executorService.shutdown();
}
public static void main(String[] args){
new Restaurant();
}
}複製代碼
廚師spa
public class Chef implements Runnable{
private MealQueue waitQueue;
private MealQueue finishedQueue;
public Chef(MealQueue waitQueue, MealQueue finishedQueue) {
this.waitQueue = waitQueue;
this.finishedQueue = finishedQueue;
}
@Override
public void run() {
try {
while (!Thread.interrupted()){
Order order =waitQueue.take();
Thread.sleep(500);
System.out.print("chef:order done "+ order.toString()+"\n");
finishedQueue.add(order);
}
} catch (Exception e) {
e.printStackTrace();
}
}
}複製代碼
服務員線程
public class Waiter implements Runnable{
private MealQueue waitQueue;
private MealQueue finishedQueue;
private int count;
public Waiter(MealQueue waitQueue, MealQueue finishedQueue) {
this.waitQueue = waitQueue;
this.finishedQueue = finishedQueue;
count=0;
}
@Override
public void run() {
try {
while (!Thread.interrupted()){
Order newOrder=new Order(count++);
waitQueue.add(newOrder);
System.out.print("waiter:a new order\n");
Order order =finishedQueue.take();
System.out.print("waiter:order complete "+ order.toString()+"\n");
}
} catch (Exception e) {
e.printStackTrace();
}
}
}複製代碼
咱們經過兩種方法完成了線程的協做,我的以爲使用BlockingQueuer更容易也更好管理。最後還有一個例子模擬生產吐司麪包,第一步製做吐司,第二步抹黃油,第三步塗果醬。代碼已同步到github,再也不贅述。如發現錯誤,歡迎指正。rest