AES加密算法(C++ 實現,附源碼)

先搞定AES算法,基本變換包括SubBytes(字節替代)、ShiftRows(行移位)、MixColumns(列混淆)、AddRoundKey(輪密鑰加)c++

其算法通常描述爲算法

明文及密鑰的組織排列方式數組

 

ByteSubstitution(字節替代)函數

非線性的字節替代,單獨處理每一個字節:加密

求該字節在有限域GF(28)上的乘法逆,"0"被映射爲自身,即對於α∈GF(28),求β∈GF(28),spa

使得α·β=β·α=1mod(x8+x4+x2+x+1)3d

對上一步求得的乘法逆做仿射變換指針

yi=xi + x(i+4)mod8 + x(i+6)mod8 + x(i+7)mod8 + cicode

(其中ci是6310即011000112的第i位),用矩陣表示爲orm

原本打算把求乘法逆和仿射變換算法敲上去,最後仍是放棄了...直接打置換表

 

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
unsigned char  sBox[] =
{ /*  0    1    2    3    4    5    6    7    8    9    a    b    c    d    e    f */
     0x63,0x7c,0x77,0x7b,0xf2,0x6b,0x6f,0xc5,0x30,0x01,0x67,0x2b,0xfe,0xd7,0xab,0x76, /*0*/ 
     0xca,0x82,0xc9,0x7d,0xfa,0x59,0x47,0xf0,0xad,0xd4,0xa2,0xaf,0x9c,0xa4,0x72,0xc0, /*1*/
     0xb7,0xfd,0x93,0x26,0x36,0x3f,0xf7,0xcc,0x34,0xa5,0xe5,0xf1,0x71,0xd8,0x31,0x15, /*2*/
     0x04,0xc7,0x23,0xc3,0x18,0x96,0x05,0x9a,0x07,0x12,0x80,0xe2,0xeb,0x27,0xb2,0x75, /*3*/
     0x09,0x83,0x2c,0x1a,0x1b,0x6e,0x5a,0xa0,0x52,0x3b,0xd6,0xb3,0x29,0xe3,0x2f,0x84, /*4*/
     0x53,0xd1,0x00,0xed,0x20,0xfc,0xb1,0x5b,0x6a,0xcb,0xbe,0x39,0x4a,0x4c,0x58,0xcf, /*5*/
     0xd0,0xef,0xaa,0xfb,0x43,0x4d,0x33,0x85,0x45,0xf9,0x02,0x7f,0x50,0x3c,0x9f,0xa8, /*6*/ 
     0x51,0xa3,0x40,0x8f,0x92,0x9d,0x38,0xf5,0xbc,0xb6,0xda,0x21,0x10,0xff,0xf3,0xd2, /*7*/
     0xcd,0x0c,0x13,0xec,0x5f,0x97,0x44,0x17,0xc4,0xa7,0x7e,0x3d,0x64,0x5d,0x19,0x73, /*8*/
     0x60,0x81,0x4f,0xdc,0x22,0x2a,0x90,0x88,0x46,0xee,0xb8,0x14,0xde,0x5e,0x0b,0xdb, /*9*/
     0xe0,0x32,0x3a,0x0a,0x49,0x06,0x24,0x5c,0xc2,0xd3,0xac,0x62,0x91,0x95,0xe4,0x79, /*a*/
     0xe7,0xc8,0x37,0x6d,0x8d,0xd5,0x4e,0xa9,0x6c,0x56,0xf4,0xea,0x65,0x7a,0xae,0x08, /*b*/
     0xba,0x78,0x25,0x2e,0x1c,0xa6,0xb4,0xc6,0xe8,0xdd,0x74,0x1f,0x4b,0xbd,0x8b,0x8a, /*c*/
     0x70,0x3e,0xb5,0x66,0x48,0x03,0xf6,0x0e,0x61,0x35,0x57,0xb9,0x86,0xc1,0x1d,0x9e, /*d*/
     0xe1,0xf8,0x98,0x11,0x69,0xd9,0x8e,0x94,0x9b,0x1e,0x87,0xe9,0xce,0x55,0x28,0xdf, /*e*/
     0x8c,0xa1,0x89,0x0d,0xbf,0xe6,0x42,0x68,0x41,0x99,0x2d,0x0f,0xb0,0x54,0xbb,0x16  /*f*/
};

 

 下面是逆置換表,解密時使用

 

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
unsigned char  invsBox[256] =
{ /*  0    1    2    3    4    5    6    7    8    9    a    b    c    d    e    f  */ 
     0x52,0x09,0x6a,0xd5,0x30,0x36,0xa5,0x38,0xbf,0x40,0xa3,0x9e,0x81,0xf3,0xd7,0xfb, /*0*/
     0x7c,0xe3,0x39,0x82,0x9b,0x2f,0xff,0x87,0x34,0x8e,0x43,0x44,0xc4,0xde,0xe9,0xcb, /*1*/
     0x54,0x7b,0x94,0x32,0xa6,0xc2,0x23,0x3d,0xee,0x4c,0x95,0x0b,0x42,0xfa,0xc3,0x4e, /*2*/
     0x08,0x2e,0xa1,0x66,0x28,0xd9,0x24,0xb2,0x76,0x5b,0xa2,0x49,0x6d,0x8b,0xd1,0x25, /*3*/
     0x72,0xf8,0xf6,0x64,0x86,0x68,0x98,0x16,0xd4,0xa4,0x5c,0xcc,0x5d,0x65,0xb6,0x92, /*4*/
     0x6c,0x70,0x48,0x50,0xfd,0xed,0xb9,0xda,0x5e,0x15,0x46,0x57,0xa7,0x8d,0x9d,0x84, /*5*/
     0x90,0xd8,0xab,0x00,0x8c,0xbc,0xd3,0x0a,0xf7,0xe4,0x58,0x05,0xb8,0xb3,0x45,0x06, /*6*/
     0xd0,0x2c,0x1e,0x8f,0xca,0x3f,0x0f,0x02,0xc1,0xaf,0xbd,0x03,0x01,0x13,0x8a,0x6b, /*7*/
     0x3a,0x91,0x11,0x41,0x4f,0x67,0xdc,0xea,0x97,0xf2,0xcf,0xce,0xf0,0xb4,0xe6,0x73, /*8*/
     0x96,0xac,0x74,0x22,0xe7,0xad,0x35,0x85,0xe2,0xf9,0x37,0xe8,0x1c,0x75,0xdf,0x6e, /*9*/
     0x47,0xf1,0x1a,0x71,0x1d,0x29,0xc5,0x89,0x6f,0xb7,0x62,0x0e,0xaa,0x18,0xbe,0x1b, /*a*/
     0xfc,0x56,0x3e,0x4b,0xc6,0xd2,0x79,0x20,0x9a,0xdb,0xc0,0xfe,0x78,0xcd,0x5a,0xf4, /*b*/
     0x1f,0xdd,0xa8,0x33,0x88,0x07,0xc7,0x31,0xb1,0x12,0x10,0x59,0x27,0x80,0xec,0x5f, /*c*/
     0x60,0x51,0x7f,0xa9,0x19,0xb5,0x4a,0x0d,0x2d,0xe5,0x7a,0x9f,0x93,0xc9,0x9c,0xef, /*d*/
     0xa0,0xe0,0x3b,0x4d,0xae,0x2a,0xf5,0xb0,0xc8,0xeb,0xbb,0x3c,0x83,0x53,0x99,0x61, /*e*/
     0x17,0x2b,0x04,0x7e,0xba,0x77,0xd6,0x26,0xe1,0x69,0x14,0x63,0x55,0x21,0x0c,0x7d  /*f*/
};

 

這裏遇到問題了,原本用純c初始化數組很正常,封裝成類之後發現不能初始化,無論是聲明、構造函數都沒法初始化,百歌谷度了一通後沒有任何答案,無奈只能在構造函數中聲明一個局部變量數組並初始化,而後用memcpy,(成員變量名爲Sbox/InvSbox,局部變量名sBox/invsBox)


1
2
3
4
5
6
7
8
9
10
11
void  AES::SubBytes(unsigned char  state[][4])
{
     int  r,c;
     for (r=0; r<4; r++)
     {
         for (c=0; c<4; c++)
         {
             state[r][c] = Sbox[state[r][c]];
         }
     }
}


 ShiftRows(行移位變換)

行移位變換完成基於行的循環位移操做,變換方法: 

即行移位變換做用於行上,第0行不變,第1行循環左移1個字節,第2行循環左移2個字節,第3行循環左移3個字節

 

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
void  AES::ShiftRows(unsigned char  state[][4])
{
     unsigned char  t[4];
     int  r,c;
     for (r=1; r<4; r++)
     {
         for (c=0; c<4; c++)
         {
             t[c] = state[r][(c+r)%4];
         }
         for (c=0; c<4; c++)
         {
             state[r][c] = t[c];
         }
     }
}


MixColumns(列混淆變換) 

 逐列混合,方法:

b(x) = (03·x3 + 01·x2 + 01·x + 02) · a(x) mod(x4 + 1)

矩陣表示形式:

 

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
void  AES::MixColumns(unsigned char  state[][4])
{
     unsigned char  t[4];
     int  r,c;
     for (c=0; c< 4; c++)
     {
         for (r=0; r<4; r++)
         {
             t[r] = state[r][c];
         }
         for (r=0; r<4; r++)
         {
             state[r][c] = FFmul(0x02, t[r])
                         ^ FFmul(0x03, t[(r+1)%4])
                         ^ FFmul(0x01, t[(r+2)%4])
                         ^ FFmul(0x01, t[(r+3)%4]);
         }
     }
}
 
unsigned char  AES::FFmul(unsigned char  a, unsigned char  b)
{
     unsigned char  bw[4];
     unsigned char  res=0;
     int  i;
     bw[0] = b;
     for (i=1; i<4; i++)
     {
         bw[i] = bw[i-1]<<1;
         if (bw[i-1]&0x80)
         {
             bw[i]^=0x1b;
         }
     }
     for (i=0; i<4; i++)
     {
         if ((a>>i)&0x01)
         {
             res ^= bw[i];
         }
     }
     return  res;
}

 

其中FFmul爲有限域GF(28)上的乘法,標準算法應該是循環8次(b與a的每一位相乘,結果相加),但這裏只用到最低2位,解密時用到的逆列混淆也只用了低4位,因此在這裏高4位的運算是多餘的,只計算低4位。

 

AddRoundKey(輪密鑰加變換) 

 簡單來講就是逐字節相加,有限域GF(28)上的加法是模2加法,即異或

 

1
2
3
4
5
6
7
8
9
10
11
void  AES::AddRoundKey(unsigned char  state[][4], unsigned char  k[][4])
{
     int  r,c;
     for (c=0; c<4; c++)
     {
         for (r=0; r<4; r++)
         {
             state[r][c] ^= k[r][c];
         }
     }
}

 

 KeyExpansion(密鑰擴展)

 將輸入的密鑰擴展爲11組128位密鑰組,其中第0組爲輸入密鑰自己 

 其後第n組第i列 爲 第n-1組第i列 與 第n組第i-1列之和(模2加法,1<= i <=3)

對於每一組 第一列即i=0,有特殊的處理

將前一列即第n-1組第3列的4個字節循環左移1個字節,

並對每一個字節進行字節替代變換SubBytes

將第一行(即第一個字節)與輪常量rc[n]相加 

最後再與前一組該列相加 

 

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
void  AES::KeyExpansion(unsigned char * key, unsigned char  w[][4][4])
{
     int  i,j,r,c;
     unsigned char  rc[] = {0x01, 0x02, 0x04, 0x08, 0x10, 0x20, 0x40, 0x80, 0x1b, 0x36};
     for (r=0; r<4; r++)
     {
         for (c=0; c<4; c++)
         {
             w[0][r][c] = key[r+c*4];
         }
     }
     for (i=1; i<=10; i++)
     {
         for (j=0; j<4; j++)
         {
             unsigned char  t[4];
             for (r=0; r<4; r++)
             {
                 t[r] = j ? w[i][r][j-1] : w[i-1][r][3];
             }
             if (j == 0)
             {
                 unsigned char  temp = t[0];
                 for (r=0; r<3; r++)
                 {
                     t[r] = Sbox[t[(r+1)%4]];
                 }
                 t[3] = Sbox[temp];
                 t[0] ^= rc[i-1];
             }
             for (r=0; r<4; r++)
             {
                 w[i][r][j] = w[i-1][r][j] ^ t[r];
             }
         }
     }
}

 

解密的基本運算

AES解密算法與加密不一樣,基本運算中除了AddRoundKey(輪密鑰加)不變外,其他的都須要進行逆變換,即

InvSubBytes(逆字節替代)、InvShiftRows(逆行移位)、InvMixColumns(逆列混淆)

 

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
void  AES::InvSubBytes(unsigned char  state[][4])
{
     int  r,c;
     for (r=0; r<4; r++)
     {
         for (c=0; c<4; c++)
         {
             state[r][c] = InvSbox[state[r][c]];
         }
     }
}
 
void  AES::InvShiftRows(unsigned char  state[][4])
{
     unsigned char  t[4];
     int  r,c;
     for (r=1; r<4; r++)
     {
         for (c=0; c<4; c++)
         {
             t[c] = state[r][(c-r+4)%4];
         }
         for (c=0; c<4; c++)
         {
             state[r][c] = t[c];
         }
     }
}
 
void  AES::InvMixColumns(unsigned char  state[][4])
{
     unsigned char  t[4];
     int  r,c;
     for (c=0; c< 4; c++)
     {
         for (r=0; r<4; r++)
         {
             t[r] = state[r][c];
         }
         for (r=0; r<4; r++)
         {
             state[r][c] = FFmul(0x0e, t[r])
                         ^ FFmul(0x0b, t[(r+1)%4])
                         ^ FFmul(0x0d, t[(r+2)%4])
                         ^ FFmul(0x09, t[(r+3)%4]);
         }
     }
}

 

加密過程

先將輸入的明文按列序組合成4*4的矩陣,直接與第0組密鑰(即輸入的密鑰)相加(異或),做爲輪加密的輸入

而後循環10次進行SubBytes、ShiftRows、MixColumns、AddRoundKey運算,最後恢復原序列

須要注意的是最後一輪並不進行MixColumns(列混淆變換)

 

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
unsigned char * AES::Cipher(unsigned char * input)
{
     unsigned char  state[4][4];
     int  i,r,c;
 
     for (r=0; r<4; r++)
     {
         for (c=0; c<4 ;c++)
         {
             state[r][c] = input[c*4+r];
         }
     }
 
     AddRoundKey(state,w[0]);
 
     for (i=1; i<=10; i++)
     {
         SubBytes(state);
         ShiftRows(state);
         if (i!=10)MixColumns(state);
         AddRoundKey(state,w[i]);
     }
 
     for (r=0; r<4; r++)
     {
         for (c=0; c<4 ;c++)
         {
             input[c*4+r] = state[r][c];
         }
     }
 
     return  input;
}

 

解密過程

 

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
unsigned char * AES::InvCipher(unsigned char * input)
{
     unsigned char  state[4][4];
     int  i,r,c;
 
     for (r=0; r<4; r++)
     {
         for (c=0; c<4 ;c++)
         {
             state[r][c] = input[c*4+r];
         }
     }
 
     AddRoundKey(state, w[10]);
     for (i=9; i>=0; i--)
     {
         InvShiftRows(state);
         InvSubBytes(state);
         AddRoundKey(state, w[i]);
         if (i)InvMixColumns(state);
     }
     
     for (r=0; r<4; r++)
     {
         for (c=0; c<4 ;c++)
         {
             input[c*4+r] = state[r][c];
         }
     }
 
     return  input;
}

 

對外部數據的加密/解密

至此已經實現了AES加密與解密的原型,在使用的時候通常處理的是字符串等,而不是直接傳入128位的數據,因此要封裝一下對外部數據的加解密處理

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
void * AES::Cipher( void * input, int  length)
{
     unsigned char * in = (unsigned char *) input;
     int  i;
     if (!length)
     {
         while (*(in+length++));
         in = (unsigned char *) input;
     }
     for (i=0; i<length; i+=16)
     {
         Cipher(in+i);
     }
     return  input;
}
 
void * AES::InvCipher( void * input, int  length)
{
     unsigned char * in = (unsigned char *) input;
     int  i;
     for (i=0; i<length; i+=16)
     {
         InvCipher(in+i);
     }
     return  input;
}

 

加密時默認參數length=0,爲要加密的數據長度,若是使用默認值,則做爲字符串處理,以'\0'爲結尾計算長度

加密時傳進的指針要預留夠16整數倍字節的空間,由於加密操做直接修改原數據,不足128位可能形成內存溢出

 

 最後附上源代碼  Source_AES_Cipher

相關文章
相關標籤/搜索