[Swift]LeetCode79. 單詞搜索 | Word Search

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➤微信公衆號:山青詠芝(shanqingyongzhi)
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➤GitHub地址:https://github.com/strengthen/LeetCode
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Given a 2D board and a word, find if the word exists in the grid.git

The word can be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same letter cell may not be used more than once.github

Example:微信

board =
[
  ['A','B','C','E'],
  ['S','F','C','S'],
  ['A','D','E','E']
]
Given word = "ABCCED", return true.
Given word = "SEE", return true.
Given word = "ABCB", return false.

給定一個二維網格和一個單詞,找出該單詞是否存在於網格中。ide

單詞必須按照字母順序,經過相鄰的單元格內的字母構成,其中「相鄰」單元格是那些水平相鄰或垂直相鄰的單元格。同一個單元格內的字母不容許被重複使用。spa

示例:code

board =
[
  ['A','B','C','E'],
  ['S','F','C','S'],
  ['A','D','E','E']
]
給定 word = "ABCCED", 返回 true.
給定 word = "SEE", 返回 true.
給定 word = "ABCB", 返回 false.

100ms
 1 class Solution {
 2     
 3     func searchSolution(_ board: inout [[Character]],
 4                         _ letter: inout [Character],
 5                         _ visited: inout [[Bool]],
 6                         _ x: Int,
 7                         _ y: Int,
 8                         _ index: Int) -> Bool {
 9         
10         if board[x][y] == letter[index] {
11             
12             visited[x][y] = true
13             
14             if (index + 1) >= letter.count {
15                 return true
16             }
17             
18             if x > 0 {
19                 if visited[x-1][y] == false && searchSolution(&board, &letter, &visited, x - 1, y, index + 1) {
20                     return true
21                 }
22             }
23             if x < (board.count - 1) {
24                 if visited[x+1][y] == false && searchSolution(&board, &letter, &visited, x + 1, y, index + 1) {
25                     return true
26                 }
27             }
28             if y > 0 {
29                 if visited[x][y-1] == false && searchSolution(&board, &letter, &visited, x, y - 1, index + 1) {
30                     return true
31                 }
32             }
33             if y < (board[0].count - 1) {
34                 if visited[x][y+1] == false && searchSolution(&board, &letter, &visited, x, y + 1, index + 1) {
35                     return true
36                 }
37             }
38             
39             visited[x][y] = false
40             
41         }
42         
43         return false
44     }
45     
46     func exist(_ board: [[Character]], _ word: String) -> Bool {
47     
48         var letters = Array(word)
49         var board = board
50         
51         if board.count <= 0 { return false }
52         if board[0].count <= 0 { return false }
53         
54         var visited = [[Bool]](repeating: [Bool](repeating: false, count: board[0].count), count: board.count)
55         
56         for x in 0..<board.count {
57             for y in 0..<board[0].count {
58                 
59                 if searchSolution(&board, &letters, &visited, x, y, 0) {
60                     return true
61                 }
62             }
63         }
64         
65         return false
66     }
67 }

128mshtm

 1 class Solution {
 2         func exist(_ board: [[Character]], _ word: String) -> Bool {
 3         
 4         if board.count == 0 {
 5             return false
 6         }
 7         let m = board.count
 8         let n = board[0].count
 9         var board = board
10         var wordChars = Array(word)
11         for i in 0..<m {
12             for j in 0..<n {
13                 if helper(&board, i, j, &wordChars, 0) {
14                     return true
15                 }
16             }
17         }
18         return false
19         
20     }
21     
22     func helper(_ board: inout [[Character]], _ i: Int, _ j: Int, _ wordChars: inout [Character], _ cur: Int) -> Bool {
23         let m = board.count
24         let n = board[0].count
25         if (i < 0 || i >= m || j < 0 || j >= n || board[i][j] == "0" || board[i][j] != wordChars[cur]) {
26             return false
27         }
28         if cur == wordChars.count - 1 {
29             return true
30         }
31         let temp = board[i][j]
32         board[i][j] = "0"
33         let res =   helper(&board, i-1, j, &wordChars, cur+1) ||
34                     helper(&board, i+1, j, &wordChars, cur+1) ||
35                     helper(&board, i, j-1, &wordChars, cur+1) ||
36                     helper(&board, i, j+1, &wordChars, cur+1)
37         board[i][j] = temp
38         return res
39     }
40 }

168msblog

 1 class Solution {
 2     func exist(_ board: [[Character]], _ word: String) -> Bool {
 3         
 4         let char = word[word.index(word.startIndex, offsetBy: 0)]
 5         
 6         for row in 0..<board.count {
 7             for col in 0..<board[0].count {
 8                 if board[row][col] == char && search(board, word, row, col, 1) { 
 9                     return true
10                 }
11             }
12         }
13         
14         return false
15     }
16     
17     func search(_ board: [[Character]], _ word: String, _ row: Int, _ col: Int, _ index: Int) -> Bool {
18         if index >= word.count { return true }
19         
20         var board = board
21         board[row][col] = "-"
22         
23         let char = word[word.index(word.startIndex, offsetBy: index)]
24          
25         if (row+1) < board.count && board[row+1][col] == char && search(board, word, row+1, col, index+1) {
26             return true
27         } 
28         
29         else if row > 0 && board[row-1][col] == char && search(board, word, row-1, col, index+1) {
30             return true
31         } 
32         
33         else if (col+1) < board[row].count && board[row][col+1] == char && search(board, word, row, col+1, index+1) {
34             return true
35         } 
36         
37         else if col > 0 && board[row][col-1] == char && search(board, word, row, col-1, index+1) {
38             return true
39         }
40         
41         return false
42     }
43 }

172ms字符串

 1 class Solution {
 2     func exist(_ board: [[Character]], _ word: String) -> Bool {
 3         var board = board
 4         var word = Array(word)
 5         for y in stride(from:0,to:board.count,by:1) {
 6             for x in stride(from:0,to:board[0].count,by:1) {
 7                 if dfs(&board,y,x,word,0) {
 8                     return true
 9                 }
10             }
11         }
12         return false
13     }
14     
15     func dfs(_ board:inout[[Character]], _ y:Int,_ x:Int,_ word:Array<Character>,_ wordPos:Int) -> Bool {
16         if wordPos == word.count {
17             return true
18         } else if y < 0 || y >= board.count || x < 0 || x >= board[0].count || board[y][x] != word[wordPos]{
19             return false
20         }
21         let temp = board[y][x]
22         board[y][x] = "#"
23         let res = dfs(&board,y + 1,x,word,wordPos + 1) || 
24         dfs(&board,y - 1,x,word,wordPos + 1) || 
25         dfs(&board,y,x + 1,word,wordPos + 1) || 
26         dfs(&board,y,x - 1,word,wordPos + 1)
27         
28         board[y][x] = temp
29         return res
30     }
31 }

192ms

 1 class Solution {
 2     let rowDirection = [0,0,1,-1]
 3     let colDiriction = [1,-1,0,0]
 4     
 5     func exist(_ board: [[Character]], _ word: String) -> Bool {
 6         guard !board.isEmpty else {
 7             return false
 8         }
 9         
10         let rowCount = board.count
11         let colCount = board[0].count
12         
13         if rowCount * colCount < word.count {
14             return false
15         }
16         
17         var wordChars = [Character](word)
18         
19         var tempBoard = board
20         
21         for rowIndex in 0..<rowCount {
22             for colIndex in 0..<colCount {  
23                 var temp = tempBoard[rowIndex][colIndex]
24                 if temp == wordChars[0]  {    
25                     tempBoard[rowIndex][colIndex] = "0"
26                     if existHelper(&tempBoard, 1, &wordChars, rowIndex, colIndex, 1, rowCount, colCount) {
27                         return true
28                     }
29                     tempBoard[rowIndex][colIndex] = temp
30                 } 
31             }
32         }
33         
34         return false
35     }
36     
37     func existHelper (_ board: inout [[Character]], _ count: Int, _ word: inout [Character], _ rowIndex: Int, _ colIndex: Int, _ index: Int, _ rowCount: Int, _ colCount: Int) -> Bool {
38             
39 
40         if count == word.count {
41             return true
42         }
43         let newCount = count + 1
44         for i in 0..<rowDirection.count {
45             let newRow = rowIndex + rowDirection[i]
46             let newCol = colIndex + colDiriction[i]
47             
48             
49             
50             if newRow < 0 || newRow >= rowCount
51             || newCol < 0 || newCol >= colCount 
52             || board[newRow][newCol] == "0" || board[newRow][newCol] != word[index] {
53                 continue 
54             }
55             
56             let newStr = board[newRow][newCol] 
57             board[newRow][newCol] = "0"
58             
59             if existHelper(&board, newCount, &word, newRow, newCol, index+1, rowCount, colCount) {
60                 return true
61             } 
62             
63             board[newRow][newCol] = newStr
64         }
65         
66         return false
67     }
68 }

316ms

 1 class Solution {
 2     func exist(_ board: [[Character]], _ word: String) -> Bool {
 3                 if board.count == 0 {
 4             return false
 5         }
 6         var visit = Array.init(repeating: Array.init(repeating: false, count: board[0].count), count: board.count)
 7         for i in 0..<board.count {
 8             for j in 0..<board[0].count {
 9                 if exist(board, word, 0, i, j, &visit) {
10                     return true
11                 }
12             }
13         }
14         return false
15 
16     }
17       func exist(_ board: [[Character]], _ word: String,_ index: Int, _ i: Int,_ j: Int, _ visit:inout [[Bool]]) -> Bool {
18         if index == word.count {//已經到字符串最後
19             return true
20         }
21         if i < 0 || j < 0 || i >= board.count || j >= board[0].count {//越界了
22             return false
23         }
24         if visit[i][j] {//訪問過了
25             return false
26         }
27         if board[i][j] != word[word.index(word.startIndex, offsetBy: index)] {
28             return false
29         }
30         //該字符符合條件,搜索下一個字符
31         visit[i][j] = true
32         let result = exist(board, word, index + 1, i + 1, j, &visit) || exist(board, word, index + 1, i - 1, j, &visit) || exist(board, word, index + 1, i , j - 1, &visit) || exist(board, word, index + 1, i , j + 1, &visit)
33         visit[i][j] = false
34         return result
35     }
36 }
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