a = 0 with open("number.txt", "r", encoding="utf8") as f: ret = f.readlines() for item in ret: print(item, type(item)) for i in item: if i.isdigit(): a+=1 print(a)
def func(**kwargs): for i in kwargs: # i是每個鍵值對得鍵 print(i,kwargs[i]) func(ok=1,yes=2,no=3) # 解析 print(i) ok yes no print(kwargs) {'ok': 1, 'yes': 2, 'no': 3} {'ok': 1, 'yes': 2, 'no': 3} {'ok': 1, 'yes': 2, 'no': 3} 因此結果是 ok 1 yes 2 no 3