Spring Cloud微服務安全實戰

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採用流行的微服務架構開發，應用程序訪問安全將會面臨更多更復雜的挑戰，尤爲是開發者最關心的三大問題：認證受權、可用性、可視化。本課程從簡單的API安全入手，過渡到複雜的微服務場景，解決上述三大問題痛點，並結合實際給出相應解決方案。幫助你們造成對安全問題的系統性思考，實戰開發一套可在中小公司落地的完整的安全方案。
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package whu.extract.pubtime.core;
import java.util.ArrayList;
import java.util.Calendar;
import java.util.Collections;
import java.util.List;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
import whu.utils.TimeUtil;
/**

• Created On 2014年3月13日 下午2:49:05

• @description 獲取網頁的發佈時間
  /
  public class FetchPubTime {
  / 表示url中連續的8位日期，
  private static String url_regwhole= "([-|/|]{1}20\d{6})";
  / 表示 用-或者/隔開的日期,有年月日的
  private static String url_reg_sepymd = "([-|/|]{1}20\d{2}[-|/|]{1}\d{1,2}[-|/|]{1}\d{1,2})";
  / 表示 用-或者/隔開的日期,只要年和月份的
  private static String url_reg_sepym = "([-|/|]{1}20\d{2}[-|/|_]{1}\d{1,2})";
  private static Calendar current = Calendar.getInstance();
  / 格式正確的時間正則表達式/
  private static String rightTimeReg = "^((\d{2}(([02468][048])|([13579][26]))[\-\/\s]?((((0?[13578])|(1[02]))[\-\/\s]?((0?[1-9])|([1-2][0-9])|(3[01])))|(((0?[469])|(11))[\-\/\s]?((0?[1-9])|([1-2][0-9])|(30)))|(0?2[\-\/\s]?((0?[1-9])|([1-2][0-9])))))|(\d{2}(([02468][1235679])|([13579][01345789]))[\-\/\s]?((((0?[13578])|(1[02]))[\-\/\s]?((0?[1-9])|([1-2][0-9])|(3[01])))|(((0?[469])|(11))[\-\/\s]?((0?[1-9])|([1-2][0-9])|(30)))|(0?2[\-\/\s]?((0?[1-9])|(1[0-9])|(2[0-8]))))))(\s(((0?[0-9])|([1-2][0-3]))\:([0-5]?[0-9])((\s)|(\:([0-5]?[0-9])))))?$";

  /**

  • @param url
  • @param urlContent

  • @return
    */
    public static String getPubTimeVarious(String url,String urlContent) {

    String pubTime = getPubTimeFromUrl(url);

    //連接裏面沒有，匹配文本中的
    if(pubTime == null)
    {
    if(urlContent!=null&&!urlContent.trim().equals(""))
    return extractPageDate(urlContent);
    }

    return pubTime;
    }

  /**從url裏面抽取動身佈時間，返回YYYY-MM-DD HH:mm:ss格式的字符串

  • @param url

  • @return
    */
    public static String getPubTimeFromUrl(String url)
    {
    Pattern p_whole = Pattern.compile(url_reg_whole);
    Matcher m_whole = p_whole.matcher(url);
    if(m_whole.find(0)&&m_whole.groupCount()>0)
    {
    String time = m_whole.group(0);
    time = time.substring(1,time.length());
    //每一步都不能夠超出當前時間
    if(current.compareTo(TimeUtil.strToCalendar(time, "yyyyMMdd"))>=0)
    {
    return time.substring(0,4)+"-"+time.substring(4,6)+"-"+
    time.substring(6,8)+" "+"00:00:00";
    }
    }

    p_whole = null;
    m_whole = null;
    Pattern p_sep = Pattern.compile(url_reg_sep_ymd);
    Matcher m_sep = p_sep.matcher(url);
    if(m_sep.find(0)&&m_sep.groupCount()>0)
    {
    String time = msep.group(0);
    time = time.substring(1,time.length());
    String[] seg = time.split("[-|/|]{1}");
    Calendar theTime = Calendar.getInstance();
    theTime.set(Calendar.YEAR,Integer.parseInt(seg[0]));
    theTime.set(Calendar.MONTH, Integer.parseInt(seg[1]));
    theTime.set(Calendar.DAY_OF_MONTH, Integer.parseInt(seg[2]));
    if(current.compareTo(theTime)>=0)
    {

    return seg[0]+"-"+seg[1]+"-"+seg[2]+" "+"00:00:00";
        }

    }
    p_sep = null;
    m_sep = null;
    Pattern p_sep_ym = Pattern.compile(url_reg_sep_ym);
    Matcher m_sep_ym = p_sep_ym.matcher(url);
    if(m_sep_ym.find(0)&&m_sep_ym.groupCount()>0)
    {
    String time = m_sepym.group(0);
    time = time.substring(1,time.length());
    Calendar theTime = Calendar.getInstance();
    String[] seg = time.split("[-|/|]{1}");
    theTime.set(Calendar.YEAR,Integer.parseInt(seg[0]));
    theTime.set(Calendar.MONTH, Integer.parseInt(seg[1]));
    theTime.set(Calendar.DAY_OF_MONTH, 1);
    if(current.compareTo(theTime)>=0)
    {

    return seg[0]+"-"+seg[1]+"-"+"01"+" "+"00:00:00";
    }

    }

    return null;
    }

  /** 從網頁源碼中取動身佈時間

  • java中正則表達式提取字符串中日期完成代碼
  • 2013年12月19日15:58:42
  • 讀取出2013-12-19 15:48:33或者2013-12-19或者2012/3/05方式的時間
  • @param text 待提取的字符串
  • @return 返回日期
  • @author: oschina

  • @Createtime: Jan 21, 2013
    */
    public static String extractPageDate(String text) {
    boolean containsHMS =false;
    String dateStr = text.replaceAll("r?n", " ");
    try {
    List matches = null;
    Pattern p_detail = Pattern.compile("(20\d{2}[-/]\d{1,2}[-/]\d{1,2} \d{1,2}:\d{1,2}:\d{1,2})|(20\d{2}年\d{1,2}月\d{1,2}日)", Pattern.CASE_INSENSITIVE|Pattern.MULTILINE);
    //假如是僅僅抽取年月日，則依照上面的，假如是抽取年月日-時分秒，則依照下面的
    Pattern p = Pattern.compile("(20\d{2}[-/]\d{1,2}[-/]\d{1,2})|(20\d{2}年\d{1,2}月\d{1,2}日)", Pattern.CASE_INSENSITIVE|Pattern.MULTILINE);
    //Matcher matcher = p.matcher(dateStr);
    Matcher matcher_detail = p_detail.matcher(dateStr);

    if(!(matcher_detail.find(0) && matcher_detail.groupCount() >= 1))
    {
        matcher_detail = p.matcher(dateStr);
        containsHMS  = true;
    }else
        matcher_detail = p_detail.matcher(dateStr);
    if (matcher_detail.find() && matcher_detail.groupCount() >= 1) {
        matches = new ArrayList();
        for (int i = 1; i <= matcher_detail.groupCount(); i++) {
            String temp = matcher_detail.group(i);
            matches.add(temp);
        }
    } else {
        matches = Collections.EMPTY_LIST;
    }           
    if (matches.size() > 0) {
        for(int i=0;i<matches.size();i++)
        {
            String pubTime = matches.get(i).toString().trim();
            //取出第一個值
            pubTime = pubTime.replace("/", "-").replace("年", "-").replace("月", "-").replace("日", "-");
            if(current.compareTo(TimeUtil.strToCalendar(pubTime, "yyyy-MM-dd"))>=0)
            {
                if(containsHMS)
                    pubTime+=" "+"00:00:00";
                if(pubTime.matches(rightTimeReg))
                {
                    return pubTime;
                }
            }
        }
    } else {
        return null;
    }

    } catch (Exception e) {return null;}return null;}}