ajax亂碼: java
前臺: ajax
var url = 'policy.do?method=searchSuggest&word=' + str+"&now="+new Date().getTime(); url
url = encodeURI(url);
url = encodeURI(url);
後臺
String word = request.getParameter("word");
word = java.net.URLDecoder.decode(word,"UTF-8");