webapi 後臺跳轉 後臺輸出html和script

1.跳轉

[HttpGet]
public HttpResponseMessage LinkTo()
{ 

HttpResponseMessage resp = new HttpResponseMessage(HttpStatusCode.Moved);

resp.Headers.Location = new Uri("http://x.com");
return resp;

}

 

2.輸出script

[HttpGet]
public HttpResponseMessage ResponseScript()
{ 

HttpResponseMessage resp =  new HttpResponseMessage();

resp.Content = new StringContent("<script>alert('xxx');window.location.href=\"about:blank\";  window.close();</script>", System.Text.Encoding.Default); //紅色標註關閉chrome當前頁,直接用window.close無做用
resp.Content.Headers.ContentType = new System.Net.Http.Headers.MediaTypeHeaderValue("text/html");
return resp;
}

 

 

From:https://www.cnblogs.com/xuejianxiyang/p/10478091.html