地址 https://www.acwing.com/problem/content/description/41/node
從上往下打印出二叉樹的每一個結點,同一層的結點按照從左到右的順序打印。spa
輸入以下圖所示二叉樹[8, 12, 2, null, null, 6, null, 4, null, null, null] 8 / \ 12 2 / 6 / 4 輸出:[8, 12, 2, 6, 4]
bfs典型例題code
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: vector<int> res; queue<TreeNode* > que; void bfs() { while(!que.empty()){ TreeNode* p = que.front(); que.pop(); res.push_back(p->val); if(p->left != NULL) que.push(p->left); if(p->right != NULL) que.push(p->right); } } vector<int> printFromTopToBottom(TreeNode* root) { if(root == NULL) return res; que.push(root); bfs(); return res; } };