csdn's FAQ:ide
一直覺得Linux裏面,那些do{}while(0)只是爲了程序的源代碼看起來比較好看而已
今天據說他是有特殊做用的,在線請教,是什麼做用?
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是爲了解決使用宏的時候煩人的分號問題。
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樓說的不是很全面,我給個例子吧
#define wait_event(wq,condition) /
do{ if(condition) break; __wait_event(wq,condition); }while(0)
這是一個奇怪的循環,它根本就只會運行一次,爲何不去掉外面的do{..}while結構呢?我曾一度在內心把它叫作「怪圈」。原來這也是很是巧妙的技巧。在工程中可能常常會引發麻煩,而上面的定義可以保證這些麻煩不會出現。下面是解釋:
假設有這樣一個宏定義
#define macro(condition) if(condition) dosomething();
如今在程序中這樣使用這個宏:
if(temp)
macro(i);
else
doanotherthing();
一切看起來很正常,可是仔細想一想。這個宏會展開成:
if(temp)
if(condition) dosomething();
else
doanotherthing();
這時的else不是與第一個if語句匹配,而是錯誤的與第二個if語句進行了匹配,編譯經過了,可是運行的結果必定是錯誤的。
爲了不這個錯誤,咱們使用do{….}while(0) 把它包裹起來,成爲一個獨立的語法單元,從而不會與上下文發生混淆。同時由於絕大多數的編譯器都可以識別do{…}while(0)這種無用的循環並進行優化,因此使用這種方法也不會致使程序的性能下降。
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但是直接用{}括起來的話,最後的分號會引發麻煩的
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但這樣就必定要在最後加分號,不能看成表達式用了。
唉,仍是儘可能避免用宏替換的方法,太容易出現問題了。性能
**************************************************************** 優化
FAQ FROM CSDN:this
Why do a lot of #defines in the kernel use do { ... } while(0)?spa
There are a couple of reasons:code
(from Dave Miller) Empty statements give a warning from the compiler so this is why you see #define FOO do { } while(0).orm
(from Dave Miller) It gives you a basic block in which to declare local variables.get
(from Ben Collins) It allows you to use more complex macros in conditional code. Imagine a macro of several lines of code like:編譯器
#define FOO(x) / printf("arg is %s/n", x); / do_something_useful(x);
if (blah == 2) FOO(blah);
if (blah == 2) printf("arg is %s/n", blah); do_something_useful(blah);;
As you can see, the if then only encompasses the printf(), and the do_something_useful() call is unconditional (not within the scope of the if), like you wanted it. So, by using a block likedo { ... } while(0), you would get this:
if (blah == 2) do { printf("arg is %s/n", blah); do_something_useful(blah); } while (0);
(from Per Persson) As both Miller and Collins point out, you want a block statement so you can have several lines of code and declare local variables. But then the natural thing would be to just use for example:
#define exch(x,y) { int tmp; tmp=x; x=y; y=tmp; }
However that wouldn't work in some cases. The following code is meant to be an if-statement with two branches:
if (x > y) exch(x,y); // Branch 1 else do_something(); // Branch 2
But it would be interpreted as an if-statement with only one branch:
if (x > y) { // Single-branch if-statement!!! int tmp; // The one and only branch consists tmp = x; // of the block. x = y; y = tmp; } ; // empty statement else // ERROR!!! "parse error before else" do_something();
The problem is the semi-colon (;) coming directly after the block. The solution for this is to sandwich the block between do and while (0). Then we have a single statement with the capabilities of a block, but not considered as being a block statement by the compiler. Our if-statement now becomes:
if (x > y) do { int tmp; tmp = x; x = y; y = tmp; } while(0); else do_something();