python處理dict轉json，字符串中存在空格問題，致使url編碼時，存在多餘字符

在進行urlencode轉換請求的參數時，一直多出一個空格，致使請求參數不正確，多了一個空格，解決方法一種是將dict中key-value鍵值對的value直接定義爲字符串，另外一種是value仍然爲字典，增長一部轉爲json字符，以後再進行編碼，dict轉爲json字符串也要注意空格問題，默認轉成的json字符串仍是有多餘的空格

 1 # -*- coding: utf-8 -*-
 2 import json
 3 from urllib import parse
 4 
 5 """ 
 6 @version: v1.0 
 7 @author: monleylu
 8 @time: 2018/2/24 10:35 
 9 """
10 urlParam = {
11     "c": {
12         "cc": 3402,
13         "ct": 10,
14         "p": 14588,
15         "ov": 20,
16         "dt": 0,
17         "v": "9.32.1"
18     }
19 }
20 ####
21 # 正常編碼結果應該爲：
22 # c=%7B%22cc%22%3A3402%2C%22ct%22%3A10%2C%22p%22%3A14588%2C%22ov%22%3A20%2C%22dt%22%3A0%2C%22v%22%3A%229.32.1%22%7D
23 # 能夠看到多了個+ 加號
24 ###
25 print("直接對字典進行編碼後結果:\r\n" + parse.urlencode(urlParam))
26 
27 
28 
29 b = {"cc":3402,"ct":10,"p":14588,"ov":20,"dt":0,"v":"9.32.1"}
30 # 能夠看到默認格式參數化時，會多出一個空格
31 print("使用默認參數轉換dict到json字符串：\r\n" + json.dumps(b))
32 
33 print("非默認參數轉換dict到json字符串：\r\n" + json.dumps(b, separators=(',', ':')))
34 a = {"c": json.dumps(b, separators=(',', ':'))}
35 print(parse.urlencode(a))
36 
37 #一種解決方法
38 urlParam["c"]=json.dumps((urlParam["c"]),separators=(',', ':'))
39 print("進行編碼後結果:\r\n" + parse.urlencode(urlParam))
40 
41 #另外一種解決方法,這種方法仍然要注意字符串中間的空格，不是太推薦這種方法
42 urlParam = { "c": '{"cc":3402,"ct":10,"p":14588,"ov":20,"dt":0,"v":"9.32.1"}'}
43 print("進行編碼後結果2:\r\n" + parse.urlencode(urlParam))

輸出結果直接對字典進行編碼後結果:c=%7B%27cc%27%3A+3402%2C+%27ct%27%3A+10%2C+%27p%27%3A+14588%2C+%27ov%27%3A+20%2C+%27dt%27%3A+0%2C+%27v%27%3A+%279.32.1%27%7D使用默認參數轉換dict到json字符串：{"cc": 3402, "ct": 10, "p": 14588, "ov": 20, "dt": 0, "v": "9.32.1"}非默認參數轉換dict到json字符串：{"cc":3402,"ct":10,"p":14588,"ov":20,"dt":0,"v":"9.32.1"}c=%7B%22cc%22%3A3402%2C%22ct%22%3A10%2C%22p%22%3A14588%2C%22ov%22%3A20%2C%22dt%22%3A0%2C%22v%22%3A%229.32.1%22%7D進行編碼後結果:c=%7B%22cc%22%3A3402%2C%22ct%22%3A10%2C%22p%22%3A14588%2C%22ov%22%3A20%2C%22dt%22%3A0%2C%22v%22%3A%229.32.1%22%7D進行編碼後結果2:c=%7B%22cc%22%3A3402%2C%22ct%22%3A10%2C%22p%22%3A14588%2C%22ov%22%3A20%2C%22dt%22%3A0%2C%22v%22%3A%229.32.1%22%7D