Lintcode 37. Reverse 3-digit Integer 反轉一個3位整數

class Solution:
    """
    @param number: A 3-digit number.
    @return: Reversed number.
    """
    def reverseInteger(self, number):
        return int(str(number)[::-1])
    
if __name__ == "__main__":
    a = input("輸入3位整數: ")
    so = Solution()
    print(so.reverseInteger(a))

測試結果git

image

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