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CF1313 C2. Skyscrapers (hard version)
時間 2020-06-10
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cf1313
c2
skyscrapers
hard
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C&C++
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C2. Skyscrapers (hard version) 題意: 求一個新的序列,使得其合最大,要求新的序列知足該序列的最大值左右兩邊(能夠只有一邊)呈非升序列。 思路: 單調棧 C1 n小模擬暴力O(n^3)也過了 C2是在C1的基礎上優化。 咱們遍歷i,默認i爲最小值,求左側的面積(假設寬都爲1) 再反向遍歷求右側每一個i對應點的面積 將兩個面積加起來-掉i那塊的面積(否則的話會算兩個i那
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