Newtonsoft.Json的初步用法

創建一個json對象並轉化爲字符輸出json

輸出結果:spa

{
  "屬性1": "內容1",
  "Data": [
    ["a1","b1","c1","d1"],
    ["a2","b2","c2","d2"],
    ["a3","b3","c3","d3"]
  ]
}code

C#代碼:對象

 1 JObject jobj = new JObject();
 2 
 3 jobj.Add("屬性1", "內容1");
 4 
 5 JArray dataArr = new JArray();
 6 dataArr.Add(new JArray(new string[] { "a1", "b1", "c1", "d1" }));
 7 dataArr.Add(new JArray(new string[] { "a2", "b2", "c2", "d2" }));
 8 dataArr.Add(new JArray(new string[] { "a3", "b3", "c3", "d3" }));
 9 jobj.Add("Data", dataArr);
10 
11 Response.Write();
12 Response.End();
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