function validfn(){ var codeArr = [1,2,3,4,5,1,2]; for( var k = 0; k < codeArr.length; k ++ ){ for( var j = k+1; j < codeArr.length; j ++ ){ if( codeArr[k] == codeArr[j]){ return showAlertInfo("fail","不能有重複的類型傾向"); } } } return true; }