店鋪 銷售日期 銷售額 A 2017-10-11 300 A 2017-10-12 200 B 2017-10-11 400 B 2017-10-12 200 A 2017-10-13 100 A 2017-10-15 100 C 2017-10-11 350 C 2017-10-15 400 C 2017-10-16 200 D 2017-10-13 500 E 2017-10-14 600 E 2017-10-15 500 D 2017-10-14 600 B 2017-10-13 300 C 2017-10-17 100
需求是:求出連續三天有銷售記錄的店鋪。sql
解法:函數
尋找每一個店鋪是否連續三天都有銷售額,利用現有的表,構造一箇中間表,中間表既有當前日期的銷售額,又有當前日期後兩天的銷售額,而後篩選銷售額大於0的店鋪的名稱便可:spa
SELECT a.Name FROM sales a LEFT JOIN sales b on a.name = b.name and DATEDIFF(STR_TO_DATE(b.day,'%Y-%m-%d'),STR_TO_DATE(a.day,'%Y-%m-%d')) = 1 LEFT JOIN sales c on b.name = c.name AND DATEDIFF(STR_TO_DATE(c.day,'%Y-%m-%d'),STR_TO_DATE(b.day,'%Y-%m-%d')) = 1 WHERE a.amount > 0 AND b.amount > 0 AND c.amount > 0;
能夠看到須要藉助str_to_date和datediff函數處理日期的差值,每一條記錄相鄰兩個日期在天數上依次添加1,不知足這樣條件的爲null值。咱們在此基礎上增長where條件過濾amount>0,並篩選出店鋪名稱便可。blog