An experiment is any action or process that generates observations.ide
The sample space of an experiment, denoted by δ, is the set of all possible outcomes of that experiment.ui
An event is any collection(subset) of outcomes contained in the sample space δ. spa
An event is said to be simple if it consists of exactly one outcome and compound if it consists of more than one outcome.orm
The following concepts from set theory will be used to construct new events from given events:ip
Given an experiment and a sample space δ, the objective of probability is to assign to each event A a number P(A), called the probability of the event A, which will give a precise measure of the chance that A will occur.ci
AXIOM1: For any event A, P(A)≥0;element
AXIOM2: P(δ) =1 rem
AXIOM3:it
PROPOSITION1:For any event A, P(A) = 1-P(A')io
PROPOSITION2:If A and B are mutually exclusive, then P(A∩B)=0
PROPOSITION3:For any two events A and B, P(AUB)=P(A)+P(B)-P(A∩B)
When the various outcomes of an experiment are equally likely, then the task of computing probabilities reduces to counting. In particular, if N is the number of outcomes in a sample space and N(A) is the number of outcomes contained in an event A, then P(A) = N(A)/N
There are, however, many experiment for which the effort involved in constructing such a list is probihitive because N is quite large. These rules are also useful in many problems involving outcomes that are not equally likely.
PROPOSITION:If the element or object of an ordered pair can be selected in n1 ways, and for each of these n1 ways the second element of the pair can be selected in n2 ways, then the number of pairs is n1n2.
Tree structure, a way of representing the hierarchical nature of a structure in a graphical form
If a six-side die is tossed five times in succession rather than just twice, the each possible outcome is an ordered collection of five number such as (1,2,3,4,1) or (5,6,2,3,4).
We will call an ordered collection of k objected a k-tuple(so a pair is 2-tuple and a triple is a 3-tuple)
Product Rule for k-Tuples
Suppose a set consists of ordered collections of k elements and that
there are n1 possible choices for the first elements;
for each choice of the first element, there are n2 possible choices of the second elements;...;for each possible choices of the first k-1 elements, there are nk choices of the kth element.
Then there are n1n2...nk possible for k-tuples.
Any ordered sequence of k objects taken from a set of n distinct objects is called a permutation of size k of the objects. The number of permutations of size k that can be constructed from the n objects is denoted by Pk,n.
For any positive integer m, m! is read "m factorial" and is defined by m!=m(m-1)...(2)(1). Also 0!=1.
Using the factorial notation yields:
Pk,n = n!/(n-k)!
Given a set of n distinct objects, any unordered subset of size k of the objects is called a combination. The number of combinations of size k that can be formed from n distinct objects will be denoted by(nk). This notation is more common in probability in Ck,n, which would be analogous to notation for permutation.
Ck,n = n!/k!(n-k)!
We will use the notation P(A|B) to represent the conditional probability of A given that the event B has occured.
For any two events A and B with P(B)>0, the conditional probability of A given that B has occured is definied by:
P(A|B) = P(A∩B)/P(B)
P(A∩B) = P(A|B)*P(B)
The multiplication rule is most useful when the experiment consists of several stages in succession.
The Law of Total Probability
Let A1,...,Ak be mutually exclusive and exhaustive events. (The events are exhaustive if one Ai must occur, so that A1U...UAk=δ)Then for any other event B,
P(B) = P(B|A1)P(A1)+...+P(B|Ak)P(Ak) = ∑P(B|Ai)P(Ai)
Bayes' Theorem
Let A1,...,Ak be mutually exclusive and exhaustive events with P(Ai)>0 for i=1,...k. Then for any other event B for which P(B)>0
P(Aj|B) = P(Aj∩B)/P(B) = P(B|Aj)P(Aj)/∑P(B|Ai)*P(Ai)
Two events A and B are independent if P(A|B) = P(A) and are dependent otherwise.
PROPOSITION: A and B are independent if and only if P(A∩B)=P(A)*P(B)
Events A1,...,An are mutually independent if for every k (k=2,3,...,n) and every subset of indices i1,i2,...,ik,
P(Ai1∩Ai2∩...∩Aik) = P(Ai1)*P(Ai2)*...*P(Aik)