涉及到取餐號的問題,每一個商家都有相對應的取餐號,這時候很難用 blockqueue來實現,想了不少辦法,首先作測試,生成一堆訂單。,而後批量改變訂單狀態。java
class ThreadTest implements Runnable{ private String testString; public ThreadTest(String test){ testString = test; } /** * 重寫(Override)run()方法 JVM會自動調用該方法 */ public void run() { String token = "token=18f78d796311bd38&"; String uri="http://localhost:8080/noodle/payOrderStatus.json?"+token+"orderid="+testString+"&orderstatus=1"; try{ HttpClient httpClient=new DefaultHttpClient(); HttpGet httpGet = new HttpGet(uri); HttpResponse resp=httpClient.execute(httpGet); if(resp.getStatusLine().getStatusCode()==HttpStatus.SC_OK){ BufferedReader reader=new BufferedReader( new InputStreamReader(resp.getEntity().getContent()) ); StringBuffer result=new StringBuffer(); String inputLine=null; while((inputLine=reader.readLine())!=null){ result.append(inputLine); } System.out.println(result.toString()); ResultModel<List<OrderDetail>> test = JSON.parseObject(result.toString(),new TypeReference<ResultModel<List<OrderDetail>>>(){}); System.out.println(test.getCode()); OrderDetail orderDetail = test.getData().get(0); System.out.println(orderDetail.getDishtype()); } }catch(Exception e){ System.out.println(e.getMessage()); } } }
使用線程池來模擬
不用sychronized就會是有重複的數據產生,若是加上則不會產生重複數據,達到預期效果。json