Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.html
You may assume no duplicates in the array.swift
Here are few examples.
[1,3,5,6], 5 → 2
[1,3,5,6], 2 → 1
[1,3,5,6], 7 → 4
[1,3,5,6], 0 → 0app
class Solution { func searchInsert(_ nums: [Int], _ target: Int) -> Int { for i in 0..<nums.count { if target <= nums[i] { return i } } return nums.count } }
Time complexity: O(n).code
Space complexity: O(1).htm
class Solution { func searchInsert(_ nums: [Int], _ target: Int) -> Int { var l = 0 var h = nums.count - 1 var m = 0 while l <= h { m = l + (h - l) / 2 if target > nums[m] { l = m + 1 } else if target < nums[m] { h = m - 1 } else { return m } } return l } }
Time complexity: O(log(n)).blog
Space complexity: O(1).leetcode
轉載請註明出處:http://www.cnblogs.com/silence-cnblogs/p/7067407.htmlget