異常:Parameter 'username' not found. Available parameters are [arg1, arg0, param1, param2]

解決方案:將----User findUserByUsernameAndPassword(String username,String password);
改成:User findUserByUsernameAndPassword(@Param("username") String username,@Param("password") String password);

 

原文出處：https://www.cnblogs.com/wuliuqi1023/p/11143149.html