常見的local variable 'x' referenced before assignment問題
def fun1():
x = 5
def fun2():
x *= 2
return x
return fun2() 如上代碼，調用fun1() 運行會出錯：UnboundLocalError: local variable 'x' referenced before assignment。python 這是由於對於fun1函數，x是局部變
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相關文章
- 1. 關於 local variable 'has' referenced before assignment 問題
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