python 檢測nginx狀態，若沒法訪問發郵件通知

應用場景:用來檢測網站可用性，訪問失敗，則發郵件通知

#!/usr/bin/env python
import urllib2,time,smtplib,string,logging from conf import * logging.basicConfig(level=logging.DEBUG, format='%(asctime)s %(filename)s[line:%(lineno)d] %(levelname)s %(message)s', datefmt='%a, %d %b %Y %H:%M:%S', filename='/var/log/status.log', filemode='a') def send_mail(name,url): HOST = "smtp.126.com" SUBJECT = name + " " + url + " " + "Domain name cannot be accessed" TO = "2712578342@qq.com" FROM = "acd34yss@126.com" text = name + " " + url BODY = string.join(( "From: %s" % FROM, "To: %s" % TO, "Subject: %s" % SUBJECT, "", text ),"\r\n") #server = smtplib.SMTP()
    #server.connect(HOST,"465")
    #server.starttls()
    server = smtplib.SMTP_SSL(HOST,"465") server.set_debuglevel(True) logging.info(server.ehlo()) server.login("acd34yss@126.com","password") server.sendmail(FROM,[TO],BODY) server.quit() def show_status(key,url): try: req = urllib2.Request(url) req.add_header('Referer', url) req.add_header('User-Agent','Mozilla/5.0 (iPhone; CPU iPhone OS 10_0_2 like Mac OS X) AppleWebKit/602.1.50 (KHTML, like Gecko) Version/10.0 Mobile/14A456 Safari/602.1',)  #目標網站是手機h5，因此請求頭模擬手機瀏覽器
        response = urllib2.urlopen(req).code except urllib2.URLError,e: send_mail(key,url[7:]) #發送郵件內容不能包含http，因此從http後面開始截取郵件內容
        logging.warning(e)  #打印錯誤日誌到文件中

def main(): for (key,url) in info['host']['all_url'].items(): show_status(key, url) time.sleep(2) if __name__=="__main__": main()