Given a binary tree, return the preorder traversal of its nodes' values.java
For example:
Given binary tree {1,#,2,3}
,node
1 \ 2 / 3
return [1,2,3]
.code
/**
* Definition for binary tree
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
import java.util.*;
public class Solution {
public ArrayList<Integer> preorderTraversal(TreeNode root) {
Stack<TreeNode> s = new Stack<TreeNode>();
ArrayList<Integer> result = new ArrayList<Integer>();
if(root == null) return result;
TreeNode node = root;
s.push(node);
while(!s.isEmpty()){
node = s.pop();
result.add(node.val);
if(node.right != null) s.push(node.right);
if(node.left != null) s.push(node.left);
}
return result;
}
}it