// example let obj = { a: 124, b: 'ccc' }; function fn(c) { return this.a + this.b + this.c; } // 使用call是這樣轉換的 // step 1: 生成新的函數,新的執行上下文(經過在傳入對象中增長調用方法) const obj = { a: 124, b: 'ccc', fn: function(c) { return this.a + this.b + this.c; } } // step2: 執行 obj.fn(333); let res = obj.fn(333); // step3: obj被改變,得恢復原來的值 delete obj.fn;
Function.prototype.myCall = function(context) { const newContext = context || window; newContext.fn = this; const args = []; for(let i = 1; i < arguments.length; i++) { args.push(arguments[i]); } const res = newContext.fn(...args); delete newContext.fn; return res; } console.log(fn.myCall(obj, 'cccc'));
Function.prototype.myApply = function(context, arr) { const newContext = context || window; newContext.fn = this; const args = []; let res; if (!arr) { res = newContext.fn(...args); } else { if (!(arr instanceof Array)) { throw new Error('params must be array'); } result = context.fn(...arr); } delete newContext.fn; return res; } console.log(fn.myApply(obj, ['cccc']));
Math.max.apply(null, [3,5,88,2])
在這裏,咱們看到了一個有趣的現象,在Math.max中能夠傳入數組
call&apply兩大做用:javascript
改變this
借用其餘對象的方法
如何實現Function.prototype.bind()
java
Function.prototype.bind = function(){ var self = this, context = [].shift.apply(arguments); args = [].slice.apply(arguments); return function(){ return self.apply(context, [].concat.apply(args, [].slice.apply(arguments))) }; } //執行 var obj = { name: 'yyh' } var func = function(a, b, c, d){ console.log(this.name); }.bind(obj, 1, 2); func(3, 4);
繼承的實現
數組
var aFn = function(){ this.name = 'yyh' } var bFn = function(){ aFn.apply(this, arguments); } bFn.prototype.getName = function(){ return this.name } //執行 var b = new bFn(); console.log(b.getName())
能借用數組的方法,Obj.array.push, 須要知足兩個條件app
var a = {c:3}; [].push.apply(a, [3,4,5]) console.log(a)