Number Theory 1_1,Pythagorean array common frmula

Q:To give integer solutions of a 2 + b 2 = c 2 a^2+b^2=c^2 a2+b2=c2 solution: We get : ( a c ) 2 + ( b c ) 2 = 1 (\frac{a}{c})^2+(\frac{b}{c})^2=1 (ca​)2+(cb​)2=1 let: a c = x \frac{a}{c}=x ca​=x b c

>>阅读原文<<