如何檢查一個字符串在Objective-C中是否包含另外一個字符串？

如何檢查字符串（ NSString ）是否包含另外一個較小的字符串？

我但願有這樣的東西：

NSString *string = @"hello bla bla";
NSLog(@"%d",[string containsSubstring:@"hello"]);

可是我能找到的最接近的是：

if ([string rangeOfString:@"hello"] == 0) {
    NSLog(@"sub string doesnt exist");
} 
else {
    NSLog(@"exists");
}

不管如何，這是查找一個字符串是否包含另外一個字符串的最佳方法嗎？

---

#1樓

NSString *myString = @"hello bla bla";
NSRange rangeValue = [myString rangeOfString:@"hello" options:NSCaseInsensitiveSearch];

if (rangeValue.length > 0)
{
    NSLog(@"string contains hello");
} 
else 
{
    NSLog(@"string does not contain hello!");
}

//您也能夠使用如下方法：

if (rangeValue.location == NSNotFound) 
{
    NSLog(@"string does not contain hello");
} 
else 
{
    NSLog(@"string contains hello!");
}

---

#2樓

Oneliner（少許代碼。DRY，由於您只有一個NSLog ）：

NSString *string = @"hello bla bla";
NSLog(@"String %@", ([string rangeOfString:@"bla"].location == NSNotFound) ? @"not found" : @"cotains bla");

---

#3樓

P i解決方案的改進版本（NSString上的類別）不只能夠告訴您是否在另外一個字符串中找到了一個字符串，並且還能夠經過引用獲取一個範圍：

@interface NSString (Contains)
-(BOOL)containsString: (NSString*)substring
              atRange:(NSRange*)range;

-(BOOL)containsString:(NSString *)substring;
@end

@implementation NSString (Contains)

-(BOOL)containsString:(NSString *)substring
              atRange:(NSRange *)range{

    NSRange r = [self rangeOfString : substring];
    BOOL found = ( r.location != NSNotFound );
    if (range != NULL) *range = r;
    return found;
}

-(BOOL)containsString:(NSString *)substring
{
    return [self containsString:substring
                        atRange:NULL];
}

@end

像這樣使用它：

NSString *string = @"Hello, World!";

//If you only want to ensure a string contains a certain substring
if ([string containsString:@"ello" atRange:NULL]) {
    NSLog(@"YES");
}

// Or simply
if ([string containsString:@"ello"]) {
    NSLog(@"YES");
}

//If you also want to know substring's range
NSRange range;
if ([string containsString:@"ello" atRange:&range]) {
    NSLog(@"%@", NSStringFromRange(range));
}

---

#4樓

這是一個複製粘貼功能代碼段：

-(BOOL)Contains:(NSString *)StrSearchTerm on:(NSString *)StrText
{
    return [StrText rangeOfString:StrSearchTerm 
        options:NSCaseInsensitiveSearch].location != NSNotFound;
}

---

#5樓

因爲這彷佛是Google的高排名結果，所以我想添加如下內容：

iOS 8和OS X 10.10將containsString:方法添加到NSString 。 這些系統的Dave DeLong示例的更新版本：

NSString *string = @"hello bla bla";
if ([string containsString:@"bla"]) {
    NSLog(@"string contains bla!");
} else {
    NSLog(@"string does not contain bla");
}