做爲Django的新手,我很難在Django 1.3中製做上傳應用程序。 我找不到任何最新的示例/代碼段。 有人能夠發佈一個最小但完整的(模型,視圖,模板)示例代碼來這樣作嗎? html
我必須說我發現django上的文檔使人困惑。 一樣對於最簡單的示例,爲何要說起表單? 我在views.py中工做的示例是:- python
for key, file in request.FILES.items(): path = file.name dest = open(path, 'w') if file.multiple_chunks: for c in file.chunks(): dest.write(c) else: dest.write(file.read()) dest.close()
html文件看起來像下面的代碼,儘管此示例僅上傳一個文件,而且用於保存文件的代碼能夠處理許多:- git
<form action="/upload_file/" method="post" enctype="multipart/form-data">{% csrf_token %} <label for="file">Filename:</label> <input type="file" name="file" id="file" /> <br /> <input type="submit" name="submit" value="Submit" /> </form>
這些示例不是個人代碼,它們是從我發現的另外兩個示例中得到的。 我是django的相對入門者,所以極可能我錯過了一些關鍵點。 github
在這裏它能夠爲您提供幫助:在models.py中建立一個文件字段 數據庫
要上傳文件(在admin.py中): django
def save_model(self, request, obj, form, change): url = "http://img.youtube.com/vi/%s/hqdefault.jpg" %(obj.video) url = str(url) if url: temp_img = NamedTemporaryFile(delete=True) temp_img.write(urllib2.urlopen(url).read()) temp_img.flush() filename_img = urlparse(url).path.split('/')[-1] obj.image.save(filename_img,File(temp_img)
並在模板中使用該字段。 服務器
我遇到了相似的問題,並由Django管理站點解決。 網絡
# models class Document(models.Model): docfile = models.FileField(upload_to='documents/Temp/%Y/%m/%d') def doc_name(self): return self.docfile.name.split('/')[-1] # only the name, not full path # admin from myapp.models import Document class DocumentAdmin(admin.ModelAdmin): list_display = ('doc_name',) admin.site.register(Document, DocumentAdmin)
更新AkseliPalén的答案 。 參見github repo ,與Django 2兼容 app
運行startproject :: ide
$ django-admin.py startproject sample
如今建立一個文件夾( sample ):
sample/ manage.py sample/ __init__.py settings.py urls.py wsgi.py
建立一個應用程序:
$ cd sample $ python manage.py startapp uploader
如今,將建立一個包含如下文件的文件夾( uploader
):
uploader/ __init__.py admin.py app.py models.py tests.py views.py migrations/ __init__.py
在sample/settings.py
將'uploader.apps.UploaderConfig'
添加到INSTALLED_APPS
並添加MEDIA_ROOT
和MEDIA_URL
,即:
INSTALLED_APPS = [ ...<other apps>... 'uploader.apps.UploaderConfig', ] MEDIA_ROOT = os.path.join(BASE_DIR, 'media') MEDIA_URL = '/media/'
在sample/urls.py
添加::
...<other imports>... from django.conf import settings from django.conf.urls.static import static from uploader import views as uploader_views urlpatterns = [ ...<other url patterns>... path('', uploader_views.home, name='imageupload'), ]+ static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
更新uploader/models.py
::
from django.db import models from django.forms import ModelForm class Upload(models.Model): pic = models.FileField(upload_to="images/") upload_date=models.DateTimeField(auto_now_add =True) # FileUpload form class. class UploadForm(ModelForm): class Meta: model = Upload fields = ('pic',)
更新uploader/views.py
::
from django.shortcuts import render from uploader.models import UploadForm,Upload from django.http import HttpResponseRedirect from django.urls import reverse # Create your views here. def home(request): if request.method=="POST": img = UploadForm(request.POST, request.FILES) if img.is_valid(): img.save() return HttpResponseRedirect(reverse('imageupload')) else: img=UploadForm() images=Upload.objects.all().order_by('-upload_date') return render(request,'home.html',{'form':img,'images':images})
在文件夾上載器中建立一個文件夾模板 ,而後建立一個文件home.html ,即sample/uploader/templates/home.html
::
<div style="padding:40px;margin:40px;border:1px solid #ccc"> <h1>picture</h1> <form action="#" method="post" enctype="multipart/form-data"> {% csrf_token %} {{form}} <input type="submit" value="Upload" /> </form> {% for img in images %} {{forloop.counter}}.<a href="{{ img.pic.url }}">{{ img.pic.name }}</a> ({{img.upload_date}})<hr /> {% endfor %} </div>
同步數據庫和運行服務器:
$ python manage.py makemigrations $ python manage.py migrate $ python manage.py runserver
我也有相似的要求。 網絡上的大多數示例都要求建立模型和建立我不想使用的表單。 這是個人最終代碼。
if request.method == 'POST': file1 = request.FILES['file'] contentOfFile = file1.read() if file1: return render(request, 'blogapp/Statistics.html', {'file': file1, 'contentOfFile': contentOfFile})
在上傳的HTML中,我寫道:
{% block content %} <h1>File content</h1> <form action="{% url 'blogapp:uploadComplete'%}" method="post" enctype="multipart/form-data"> {% csrf_token %} <input id="uploadbutton" type="file" value="Browse" name="file" accept="text/csv" /> <input type="submit" value="Upload" /> </form> {% endblock %}
如下是顯示文件內容的HTML:
{% block content %} <h3>File uploaded successfully</h3> {{file.name}} </br>content = {{contentOfFile}} {% endblock %}