在數據庫開發過程當中,咱們要爲每種類型的數據取出前幾條記錄,或者是取最新、最小、最大等等,這個該如何實現呢,本文章向你們介紹如何實現mysql分組取最大(最小、最新、前N條)條記錄。須要的能夠參考一下。mysql
先看一下本示例中須要使用到的數據sql
建立表並插入數據:數據庫
insert into tb values('a', 2, 'a2'); insert into tb values('a', 1, 'a1'); insert into tb values('a', 3, 'a3'); insert into tb values('b', 1, 'b1'); insert into tb values('b', 3, 'b3'); insert into tb values('b', 2, 'b2'); insert into tb values('b', 4, 'b4'); insert into tb values('b', 5, 'b5');
數據表以下:spa
name | val | memo |
a | 2 | a2 |
a | 1 | a1 |
a | 3 | a3 |
b | 1 | b1 |
b | 3 | b3 |
b | 2 | b2 |
b | 4 | b4 |
b | 5 | b5 |
方法一:code
select a.* from tb a where val = (select max(val) from tb where name = a.name) order by a.name
方法二:server
select a.* from tb a where not exists(select 1 from tb where name = a.name and val > a.val)
方法三:開發
select a.* from tb a,(select name,max(val) val from tb group by name) b where a.name = b.name and a.val = b.val order by a.name
方法四:it
select a.* from tb a inner join (select name , max(val) val from tb group by name) b on a.name = b.name and a.val = b.val order by
方法五:table
select a.* from tb a where 1 > (select count(*) from tb where name = a.name and val > a.val ) order by a.name
方法六:效率
select * from (select * from tb ORDER BY val desc) temp GROUP BY name ORDER BY val desc;
以上六種方法運行的結果均爲以下所示:
name | val | memo |
a | 3 | a3 |
b | 5 | b5 |
小編推薦使用第1、第3、第四鍾方法,結果顯示第1,3,4種方法效率相同,第2,5種方法效率差些。
方法一:
select a.* from tb a where val = (select min(val) from tb where name = a.name) order by a.name
方法二:
select a.* from tb a where not exists(select 1 from tb where name = a.name and val < a.val)
方法三:
select a.* from tb a,(select name,min(val) val from tb group by name) b where a.name = b.name and a.val = b.val order by a.name
方法四:
select a.* from tb a inner join (select name , min(val) val from tb group by name) b on a.name = b.name and a.val = b.val order by a.name
方法五:
select a.* from tb a where 1 > (select count(*) from tb where name = a.name and val < a.val) order by a.name
以上五種方法運行的結果均爲以下所示:
name | val | memo |
a | 1 | a1 |
b | 1 | b1 |
sql以下:
select a.* from tb a where val = (select top 1 val from tb where name = a.name) order by a.name //這個是sql server的 //mysql應該是 select a.* from tb a where val = (select val from tb where name = a.name limit 1) order by a.name
結果以下:
name | val | memo |
a | 2 | a2 |
b | 1 | b1 |
第一種方法:
select a.* from tb a where 2 > (select count(*) from tb where name = a.name and val < a.val ) order by a.name,a.val
第二種方法:
select a.* from tb a where val in (select top 2 val from tb where name=a.name order by val) order by a.name,a.val
第三種方法:
select a.* from tb a where exists (select count(*) from tb where name = a.name and val < a.val having Count(*) < 2) order by a.name
結果以下:
name | val | memo |
a | 1 | a1 |
a | 2 | a2 |
b | 1 | b1 |
b | 2 | b2 |
第一種方法:
select a.* from tb a where 2 > (select count(*) from tb where name = a.name and val > a.val ) order by a.name,a.val
第二種方法:
select a.* from tb a where val in (select top 2 val from tb where name=a.name order by val desc) order by a.name,a.val
第三種方法:
select a.* from tb a where exists (select count(*) from tb where name = a.name and val > a.val having Count(*) < 2) order by a.name
結果以下:
name | val | memo |
a | 3 | a3 |
a | 2 | a2 |
b | 5 | b5 |
b | 4 | b4 |