C# 寫 LeetCode easy #28 Implement strStr()

2八、Implement strStr()

Implement strStr().

Return the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack.

Example 1:

Input: haystack = "hello", needle = "ll"
Output: 2

Example 2:

Input: haystack = "aaaaa", needle = "bba"
Output: -1

Clarification:

What should we return when needle is an empty string? This is a great question to ask during an interview.

For the purpose of this problem, we will return 0 when needle is an empty string. This is consistent to C's strstr() and Java's indexOf().

 

代碼：

static void Main(string[] args)
        {
            var haystack = "hello";
            var needle = "ll";

            var res = ImplementstrStr(haystack, needle);
            Console.WriteLine(res);
            Console.ReadKey();
        }

        private static int ImplementstrStr(string haystack, string needle)
        {
            var match = true;
            for (var i = 0; i <= haystack.Length - needle.Length; i++)
            {
                match = true;
                for (var j = 0; j < needle.Length; j++)
                {
                    if (haystack[i + j] != needle[j])
                    {
                        match = false;
                        break;
                    }
                }
                if (match) return i;
            }
            return -1;

 

解析：

輸入：字符串

輸出：匹配位置

思想：定義一個匹配變量match，從首字母循環，使用內循環逐一判斷是否每一個字母都能匹配，若不匹配馬上退出內循環。

時間複雜度：O(m*n)  m和n分別是兩個字符串長度。