dp[i][0]表示從i點及其子樹中買入的最大收益(負數)ios
dp[i][1]表示從i點及其子樹中賣出的最大收益(正數)c++
#include <bits/stdc++.h> #define INF 0x3f3f3f3f #define full(a, b) memset(a, b, sizeof a) #define FAST_IO ios::sync_with_stdio(false), cin.tie(0), cout.tie(0) using namespace std; typedef long long ll; inline int lowbit(int x){ return x & (-x); } inline int read(){ int ret = 0, w = 0; char ch = 0; while(!isdigit(ch)) { w |= ch == '-'; ch = getchar(); } while(isdigit(ch)) ret = (ret << 3) + (ret << 1) + (ch ^ 48), ch = getchar(); return w ? -ret : ret; } inline int gcd(int a, int b){ return b ? gcd(b, a % b) : a; } inline int lcm(int a, int b){ return a / gcd(a, b) * b; } template <typename T> inline T max(T x, T y, T z){ return max(max(x, y), z); } template <typename T> inline T min(T x, T y, T z){ return min(min(x, y), z); } template <typename A, typename B, typename C> inline A fpow(A x, B p, C lyd){ A ans = 1; for(; p; p >>= 1, x = 1LL * x * x % lyd)if(p & 1)ans = 1LL * x * ans % lyd; return ans; } const int N = 100005; int _, n, w[N], head[N], cnt, dp[N][2], ans; struct Edge { int v, next, w; } edge[N<<1]; void build(){ cnt = 0, ans = -INF; full(head, -1), full(w, 0); } void addEdge(int a, int b, int c){ edge[cnt].v = b, edge[cnt].next = head[a], edge[cnt].w = c, head[a] = cnt ++; } void dfs(int s, int fa){ dp[s][0] = -w[s], dp[s][1] = w[s]; for(int i = head[s]; i != -1; i = edge[i].next){ int u = edge[i].v; if(u == fa) continue; dfs(u, s); dp[s][0] = max(dp[s][0], dp[u][0] - edge[i].w); dp[s][1] = max(dp[s][1], dp[u][1] - edge[i].w); } ans = max(ans, dp[s][0] + dp[s][1]); } int main(){ for(_ = read(); _; _ --){ build(); n = read(); for(int i = 1; i <= n; i ++) w[i] = read(); for(int i = 0; i < n - 1; i ++){ int u = read(), v = read(), c = read(); addEdge(u, v, c), addEdge(v, u, c); } dfs(1, 0); printf("%d\n", ans); } return 0; }