Content-Type: application/x-www-form-urlencoded;charset=utf-8java
request body中的參數格式:userName=adminicxp&userPassword=123qwe!@#spring
這種方式能夠用 request.getParameter的方式來得到。json
Content-Type: application/json; charset=utf-8數組
request body中的參數格式:mvc
{ "userName": "adminicxp", "userPassword": "123qwe!@#", "sysId": "xxx" }
這種方式經過以下方式得到:app
@RequestMapping("/xxx") @ResponseBody public String xxx(HttpServletRequest request) throws IOException { String jsonString = getBodyString(request.getReader()); JSONObject jbJsonObject = new JSONObject().fromObject(jsonString); User user = (User) JSONObject.toBean(jbJsonObject, User.class); System.out.println(jbJsonObject); System.out.println("id:" + user.getUserName());return null; } @RequestMapping("/xxx2") @ResponseBody public String xxx2(User user) throws IOException { System.out.println("---------------"); System.out.println(user.getUserName()); System.out.println(user.getPassWord()); System.out.println("---------------"); if (true) { return "success"; } else { return "fail"; } }
public String getBodyString(BufferedReader br) {
String inputLine;
String str = "";
try {
while ((inputLine = br.readLine()) != null) {
str += inputLine;
}
br.close();
} catch (IOException e) {
System.out.println("IOException: " + e);
}
return str;
}post
方式1:url
springmvc 後臺java代碼spa
@RequestBody Map<String, List<String>> param List<String> ids = param.get("ids");
fiddler 請求code
Content-Type指定爲 application/json RequestBody格式:{"ids":["first0001company", "xxx4234324"]}
方式2:
springmvc 後臺java代碼
@RequestParam List<String> ids; 或者 @RequestParam String[] ids;
fiddler 請求
Content-Type指定爲 application/x-www-form-urlencoded RequestBody格式:ids=first0001company&ids=xxx4234324