獲取當前時區的時間component
[NSDate date]獲取的是GMT時間,要想得到某個時區的時間,如下代碼能夠解決這個問題字符串
NSDate *date = [NSDate date];get
NSTimeZone *zone = [NSTimeZone systemTimeZone];it
NSInteger interval = [zone secondsFromGMTForDate: date];date
NSDate *localeDate = [date dateByAddingTimeInterval: interval]; im
NSLog(@"%@", localeDate);di
獲取date中的年月日時分秒 星期時間
-(NSString *)getDayWeek:(int)dayDelay{ co
NSString *weekDay;字符
NSDate *dateNow;
dateNow=[NSDate dateWithTimeIntervalSinceNow:dayDelay*24*60*60];//dayDelay表明向後推幾天,若是是0則表明是今天,若是是1就表明向後推24小時,若是想向後推12小時,就能夠改爲dayDelay*12*60*60,讓dayDelay=1
NSCalendar *calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];//設置成中國陽曆
NSDateComponents *comps = [[NSDateComponents alloc] init];
NSInteger unitFlags = NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit | NSWeekdayCalendarUnit | NSHourCalendarUnit | NSMinuteCalendarUnit | NSSecondCalendarUnit;//這句我也不明白具體時用來作什麼。。。
comps = [calendar components:unitFlags fromDate:dateNow];
long weekNumber = [comps weekday]; //獲取星期對應的長整形字符串
long day=[comps day];//獲取日期對應的長整形字符串
long year=[comps year];//獲取年對應的長整形字符串
long month=[comps month];//獲取月對應的長整形字符串
long hour=[comps hour];//獲取小時對應的長整形字符串
long minute=[comps minute];//獲取月對應的長整形字符串
long second=[comps second];//獲取秒對應的長整形字符串
持續更新中