關於 count 函數的使用一直存在爭議,尤爲是在 MySQL 中,做爲流行度愈來愈高的 PostgreSQL 是否也有相似的問題呢,咱們經過實踐來理解一下 PostgreSQL 中 count 函數的行爲。html
建立測試數據庫,並建立測試表。測試表中有自增 ID、建立時間、內容三個字段,自增 ID 字段是主鍵。sql
create database performance_test;
create table test_tbl (id serial primary key, created_at timestamp, content varchar(512));
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使用 generate_series 函數生成自增 ID,使用 now() 函數生成 created_at 列,對於 content 列,使用了 repeat(md5(random()::text), 10) 生成 10 個 32 位長度的 md5 字符串。使用下列語句,插入 1000w 條記錄用於測試。數據庫
performance_test=# insert into test_tbl select generate_series(1,10000000),now(),repeat(md5(random()::text),10);
INSERT 0 10000000
Time: 212184.223 ms (03:32.184)
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默認狀況下 PostgreSQL 不開啓 SQL 執行時間的顯示,因此須要手動開啓一下,方便後面的測試對比。緩存
\timing on
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count(*) 和 count(1) 的性能區別是常常被討論的問題,分別使用 count(*) 和 count(1) 執行一次查詢。bash
performance_test=# select count(*) from test_tbl;
count
----------
10000000
(1 row)
Time: 115090.380 ms (01:55.090)
performance_test=# select count(1) from test_tbl;
count
----------
10000000
(1 row)
Time: 738.502 ms
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能夠看到兩次查詢的速度差異很是大,count(1) 真的有這麼大的性能提高?接下來再次運行查詢語句。app
performance_test=# select count(*) from test_tbl;
count
----------
10000000
(1 row)
Time: 657.831 ms
performance_test=# select count(1) from test_tbl;
count
----------
10000000
(1 row)
Time: 682.157 ms
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能夠看到第一次查詢時候會很是的慢,後面三次速度很是快而且時間相近,這裏就有兩個問題出現了:dom
使用 explain 語句從新執行查詢語句ide
explain (analyze,buffers,verbose) select count(*) from test_tbl;
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能夠看到以下輸出:函數
Finalize Aggregate (cost=529273.69..529273.70 rows=1 width=8) (actual time=882.569..882.570 rows=1 loops=1)
Output: count(*)
Buffers: shared hit=96 read=476095
-> Gather (cost=529273.48..529273.69 rows=2 width=8) (actual time=882.492..884.170 rows=3 loops=1)
Output: (PARTIAL count(*))
Workers Planned: 2
Workers Launched: 2
Buffers: shared hit=96 read=476095
-> Partial Aggregate (cost=528273.48..528273.49 rows=1 width=8) (actual time=881.014..881.014 rows=1 loops=3)
Output: PARTIAL count(*)
Buffers: shared hit=96 read=476095
Worker 0: actual time=880.319..880.319 rows=1 loops=1
Buffers: shared hit=34 read=158206
Worker 1: actual time=880.369..880.369 rows=1 loops=1
Buffers: shared hit=29 read=156424
-> Parallel Seq Scan on public.test_tbl (cost=0.00..517856.98 rows=4166598 width=0) (actual time=0.029..662.165 rows=3333333 loops=3)
Buffers: shared hit=96 read=476095
Worker 0: actual time=0.026..661.807 rows=3323029 loops=1
Buffers: shared hit=34 read=158206
Worker 1: actual time=0.030..660.197 rows=3285513 loops=1
Buffers: shared hit=29 read=156424
Planning time: 0.043 ms
Execution time: 884.207 ms
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注意裏面的 shared hit,表示命中了內存中緩存的數據,這就能夠解釋爲何後面的查詢會比第一次快不少。接下來去掉緩存,並重啓 PostgreSQL。oop
service postgresql stop
echo 1 > /proc/sys/vm/drop_caches
service postgresql start
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從新執行 SQL 語句,速度慢了不少。
Finalize Aggregate (cost=529273.69..529273.70 rows=1 width=8) (actual time=50604.564..50604.564 rows=1 loops=1)
Output: count(*)
Buffers: shared read=476191
-> Gather (cost=529273.48..529273.69 rows=2 width=8) (actual time=50604.508..50606.141 rows=3 loops=1)
Output: (PARTIAL count(*))
Workers Planned: 2
Workers Launched: 2
Buffers: shared read=476191
-> Partial Aggregate (cost=528273.48..528273.49 rows=1 width=8) (actual time=50591.550..50591.551 rows=1 loops=3)
Output: PARTIAL count(*)
Buffers: shared read=476191
Worker 0: actual time=50585.182..50585.182 rows=1 loops=1
Buffers: shared read=158122
Worker 1: actual time=50585.181..50585.181 rows=1 loops=1
Buffers: shared read=161123
-> Parallel Seq Scan on public.test_tbl (cost=0.00..517856.98 rows=4166598 width=0) (actual time=92.491..50369.691 rows=3333333 loops=3)
Buffers: shared read=476191
Worker 0: actual time=122.170..50362.271 rows=3320562 loops=1
Buffers: shared read=158122
Worker 1: actual time=14.020..50359.733 rows=3383583 loops=1
Buffers: shared read=161123
Planning time: 11.537 ms
Execution time: 50606.215 ms
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shared read 表示沒有命中緩存,經過這個現象能夠推斷出,上一小節的四次查詢中,第一次查詢沒有命中緩存,剩下三次查詢都命中了緩存。
接下來探究 count(1) 和 count(*) 的區別是什麼,繼續思考最開始的四次查詢,第一次查詢使用了 count(*),第二次查詢使用了 count(1) ,卻依然命中了緩存,不正是說明 count(1) 和 count(*) 是同樣的嗎?
事實上,PostgreSQL 官方對於 is there a difference performance-wise between select count(1) and select count(*)? 問題的回覆也證明了這一點:
Nope. In fact, the latter is converted to the former during parsing.[2]
既然 count(1) 在性能上沒有比 count(*) 更好,那麼使用 count(*) 就是更好的選擇。
接下來測試一下,在不一樣數據量大小的狀況下 count(*) 的速度,將查詢語句寫在 count.sql 文件中,使用 pgbench 進行測試。
pgbench -c 5 -t 20 performance_test -r -f count.sql
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分別測試 200w - 1000w 數據量下的 count 語句耗時
數據大小 | count耗時(ms) |
---|---|
200w | 738.758 |
300w | 1035.846 |
400w | 1426.183 |
500w | 1799.866 |
600w | 2117.247 |
700w | 2514.691 |
800w | 2526.441 |
900w | 2568.240 |
1000w | 2650.434 |
繪製成耗時曲線
曲線的趨勢在 600w - 700w 數據量之間出現了轉折,200w - 600w 是線性增加,600w 以後 count 的耗時就基本相同了。使用 explain 語句分別查看 600w 和 700w 數據時的 count 語句執行。
700w:
Finalize Aggregate (cost=502185.93..502185.94 rows=1 width=8) (actual time=894.361..894.361 rows=1 loops=1)
Output: count(*)
Buffers: shared hit=16344 read=352463
-> Gather (cost=502185.72..502185.93 rows=2 width=8) (actual time=894.232..899.763 rows=3 loops=1)
Output: (PARTIAL count(*))
Workers Planned: 2
Workers Launched: 2
Buffers: shared hit=16344 read=352463
-> Partial Aggregate (cost=501185.72..501185.73 rows=1 width=8) (actual time=889.371..889.371 rows=1 loops=3)
Output: PARTIAL count(*)
Buffers: shared hit=16344 read=352463
Worker 0: actual time=887.112..887.112 rows=1 loops=1
Buffers: shared hit=5459 read=118070
Worker 1: actual time=887.120..887.120 rows=1 loops=1
Buffers: shared hit=5601 read=117051
-> Parallel Index Only Scan using test_tbl_pkey on public.test_tbl (cost=0.43..493863.32 rows=2928960 width=0) (actual time=0.112..736.376 rows=2333333 loops=3)
Index Cond: (test_tbl.id < 7000000)
Heap Fetches: 2328492
Buffers: shared hit=16344 read=352463
Worker 0: actual time=0.107..737.180 rows=2344479 loops=1
Buffers: shared hit=5459 read=118070
Worker 1: actual time=0.133..737.960 rows=2327028 loops=1
Buffers: shared hit=5601 read=117051
Planning time: 0.165 ms
Execution time: 899.857 ms
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600w:
Finalize Aggregate (cost=429990.94..429990.95 rows=1 width=8) (actual time=765.575..765.575 rows=1 loops=1)
Output: count(*)
Buffers: shared hit=13999 read=302112
-> Gather (cost=429990.72..429990.93 rows=2 width=8) (actual time=765.557..770.889 rows=3 loops=1)
Output: (PARTIAL count(*))
Workers Planned: 2
Workers Launched: 2
Buffers: shared hit=13999 read=302112
-> Partial Aggregate (cost=428990.72..428990.73 rows=1 width=8) (actual time=763.821..763.821 rows=1 loops=3)
Output: PARTIAL count(*)
Buffers: shared hit=13999 read=302112
Worker 0: actual time=762.742..762.742 rows=1 loops=1
Buffers: shared hit=4638 read=98875
Worker 1: actual time=763.308..763.308 rows=1 loops=1
Buffers: shared hit=4696 read=101570
-> Parallel Index Only Scan using test_tbl_pkey on public.test_tbl (cost=0.43..422723.16 rows=2507026 width=0) (actual time=0.053..632.199 rows=2000000 loops=3)
Index Cond: (test_tbl.id < 6000000)
Heap Fetches: 2018490
Buffers: shared hit=13999 read=302112
Worker 0: actual time=0.059..633.156 rows=1964483 loops=1
Buffers: shared hit=4638 read=98875
Worker 1: actual time=0.038..634.271 rows=2017026 loops=1
Buffers: shared hit=4696 read=101570
Planning time: 0.055 ms
Execution time: 770.921 ms
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根據以上現象推斷,PostgreSQL 彷佛在 count 的數據量小於數據表長度的某一比例時,才使用 index scan,經過查看官方 wiki 也能夠看到相關描述:
It is important to realise that the planner is concerned with minimising the total cost of the query. With databases, the cost of I/O typically dominates. For that reason, "count(*) without any predicate" queries will only use an index-only scan if the index is significantly smaller than its table. This typically only happens when the table's row width is much wider than some indexes'.[3]
根據 Stackoverflow 上的回答,count 語句查詢的數量大於表大小的 3/4 時候就會用使用全表掃描代替索引掃描[4]。
[2] Re: performance difference in count(1) vs. count(*)?