Given a linked list, rotate the list to the right by k places, where k is non-negative.
Note:code
Example:ip
Example 1: Input: 1->2->3->4->5->NULL, k = 2 Output: 4->5->1->2->3->NULL Explanation: rotate 1 steps to the right: 5->1->2->3->4->NULL rotate 2 steps to the right: 4->5->1->2->3->NULL Example 2: Input: 0->1->2->NULL, k = 4 Output: 2->0->1->NULL Explanation: rotate 1 steps to the right: 2->0->1->NULL rotate 2 steps to the right: 1->2->0->NULL rotate 3 steps to the right: 0->1->2->NULL rotate 4 steps to the right: 2->0->1->NULL
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* rotateRight(ListNode* head, int k) { if (!head) return NULL; ListNode* cur = head; int n = 1; while(cur->next){ n++; cur = cur->next; } cur ->next = head; int m = n - k%n; for (int i = 0; i < m; ++i) { cur = cur->next; } ListNode *newhead = cur -> next; cur->next = NULL; return newhead; } };