分組中的第一條:
select * from
(
select row_number() over(partition by 列1,列2,... order by 列1,列2,...) as rownum -- 排序並分組
, * -- 所需顯示的字段
from 表
) as T
where T.rownum = 1
顯示聚合之外的列:
SELECT
a.examroomnum ,
a.positionnum ,
a.人數 ,
a.suminterviewscore ,
a.avginterviewscore ,
b.Department
FROM
(
SELECT
examroomnum ,
positionnum ,
COUNT
(*)
AS
人數 ,
SUM
(interviewscore) suminterviewscore ,
AVG
(interviewscore) avginterviewscore
FROM
examinee
GROUP
BY
examroomnum ,
positionnum
) a
LEFT
JOIN
examinee b
ON
a.examroomnum = b.examroomnum
AND
a.positionnum = b.positionnum
HAVING語句一般與GROUP BY語句聯合使用,用來過濾由GROUP BY語句返回的記錄集。sql
HAVING語句的存在彌補了WHERE關鍵字不能與聚合函數聯合使用的不足。express
語法:函數
SELECT column1, column2, ... column_n, aggregate_function (expression)FROM tablesWHERE predicatesGROUP BY column1, column2, ... column_nHAVING condition1 ... condition_n;spa
一樣使用本文中的學生表格,若是想查詢平均分高於80分的學生記錄能夠這樣寫:code
SELECT id, COUNT(course) as numcourse, AVG(score) as avgscore排序
FROM studentget
GROUP BY idit
HAVING AVG(score)>=80;io
在這裏,若是用WHERE代替HAVING就會出錯。table
使用示例************************************************************************************
計算每種物料入庫總數大於當前庫存的最先一筆入庫的時間
select productid,inamount,DATEDIFF(day,operatedate,getdate()) from(
select row_number() over(partition by productid order by operatedate) as rownum,*
from (select p.productid,p.inamount,k.operatedate from
(select productid,isnull(sum(amount),0) as inamount from P_ProductBillSumTab a with(nolock)
where tagid in ('1101','1102','1105','1106') group by productid having isnull(sum(amount),0)>(select sum(storage) as storate from p_productbatchtab b with(nolock)
where productid=a.productid)) p
left join P_ProductBillSumTab k with(nolock) on k.productid=p.productid) as mm) as T
where T.rownum = 1 order by operatedate
****************************************************************************************************
select *,DATEDIFF(day,t.operatedate,getdate()) from ((select row_number() over(partition by productid order by samount) as rownum,* from(select aa.*,c.storage from (select productid,amount,operatedate,(select SUM(amount) from product_inlist b where b.productid=a.productid and b.id>=a.id) as samountfrom product_inlist a)aaleft join product_storage c on c.productid=aa.productidwhere samount>c.storage ) k )) as T where T.rownum = 1order by operatedate desc