問題:spa
Write a SQL query to get the nth highest salary from the Employee
table.code
+----+--------+ | Id | Salary | +----+--------+ | 1 | 100 | | 2 | 200 | | 3 | 300 | +----+--------+
For example, given the above Employee table, the nth highest salary where n = 2 is 200
. If there is no nth highest salary, then the query should return null
.get
+------------------------+ | getNthHighestSalary(2) | +------------------------+ | 200 | +------------------------+
① 這道題是以前那道Second Highest Salary的拓展,根據以前那道題的作法,咱們能夠很容易的將其推展爲N,根據對Second Highest Salary中①的分析,咱們只須要將OFFSET後面的1改成N-1就好了,能夠在前面加一個SET N = N - 1,將N先變成N-1。1019 msit
CREATE FUNCTION getNthHighestSalary(N INT) RETURNS INT
BEGIN
SET N = N - 1;
RETURN (
SELECT Salary FROM Employee
GROUP BY Salary
ORDER BY Salary DESC
LIMIT 1
OFFSET N
);
ENDtable
CREATE FUNCTION getNthHighestSalary(N INT) RETURNS INT
BEGIN
SET N = N - 1;
RETURN (
SELECT DISTINCT Salary FROM Employee
ORDER BY Salary DESC
LIMIT 1
OFFSET N
);
ENDtab
② 根據對Second Highest Salary中④的分析,咱們只須要將其1改成N-1便可。2278 msquery
CREATE FUNCTION getNthHighestSalary(N INT) RETURNS INT
BEGIN
RETURN (
SELECT MAX(e1.Salary) FROM Employee E1
WHERE N - 1 =
(SELECT COUNT(DISTINCT(E2.Salary)) FROM Employee E2
WHERE E2.Salary > E1.Salary)
);
ENDco