[Swift]LeetCode288. 惟一單詞縮寫 $ Unique Word Abbreviation

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An abbreviation of a word follows the form <first letter><number><last letter>. Below are some examples of word abbreviations:

a) it                      --> it    (no abbreviation)

     1
b) d|o|g                   --> d1g

              1    1  1
     1---5----0----5--8
c) i|nternationalizatio|n  --> i18n

              1
     1---5----0
d) l|ocalizatio|n          --> l10n

Assume you have a dictionary and given a word, find whether its abbreviation is unique in the dictionary. A word's abbreviation is unique if no other word from the dictionary has the same abbreviation.

Example: 

Given dictionary = [ "deer", "door", "cake", "card" ]

isUnique("dear") -> 
isUnique("cart") -> 
isUnique("cane") -> 
isUnique("make") -> falsetruefalsetrue

---

單詞的縮寫詞遵循形式<first letter><number><last letter>。如下是單詞縮寫的一些示例：

a) it                      --> it    (無縮寫)

     1
b) d|o|g                   --> d1g

              1    1  1
     1---5----0----5--8
c) i|nternationalizatio|n  --> i18n

              1
     1---5----0
d) l|ocalizatio|n          --> l10n

假設你有一本字典並給了一個單詞，找出它的縮寫在字典中是否惟一。若是字典中沒有其餘單詞具備相同的縮寫，則單詞的縮寫是惟一的。

例子：

給定 dictionary = [ "deer", "door", "cake", "card" ]

isUnique("dear") -> 
isUnique("cart") -> 
isUnique("cane") -> 
isUnique("make") -> falsetruefalsetrue

---

Solution:

 1 class Solution {
 2     var m:[String:Set<String>] = [String:Set<String>]()
 3     func ValidWordAbbr(_ dictionary:inout [String]) {
 4         for a in dictionary
 5         {
 6             let arr:[Character] = Array(a)
 7             let k:String = String(arr[0]) + String(a.count - 2) + String(arr.last!)
 8             m[k,default:Set<String>()].insert(a)
 9         }
10     }
11     
12     func isUnique(_ word:String) -> Bool
13     {
14         let arr:[Character] = Array(word)
15         let k:String = String(arr[0]) + String(word.count - 2) + String(arr.last!)
16         let num:Int = m[k,default:Set<String>()].contains(word) ? 1 : 0
17         return num == m[k,default:Set<String>()].count
18     }
19 }

---

點擊：Playground測試

 1 var sol = Solution()
 2 var arr:[String] = [ "deer", "door", "cake", "card" ]
 3 sol.ValidWordAbbr(&arr)
 4 print(sol.isUnique("dear"))
 5 //Print false
 6 print(sol.isUnique("cart"))
 7 //Print true
 8 print(sol.isUnique("cane"))
 9 //Print false
10 print(sol.isUnique("make"))
11 //Print true