查詢部門工資前三高的員工。html
我用的數據庫是oracle。 下面是數據表的信息。 Employee表數據:mysql
| ID | NAME | Salary | DepartmentId | | -- | ---- | ------ | ------------ | |1 | Joe | 85000 | 1 | |2 | Henry | 80000 | 2 | |3 | Sam | 60000 | 2 | |4 | Max | 90000 | 1 | |5 | Janet | 69000 | 1 | |6 | Randy | 85000 | 1 | |7 | Will | 70000 | 1 | |8 | edav | 50000 | 2 | |9 | easonv | 40000 | 2 |
八、9行爲我自行添加,爲了更清晰展現查詢結果。sql
Employee 表包含全部員工信息,每一個員工有其對應的 Id, salary 和 department Id 。數據庫
create table Employee ( Id number(5), Name varchar2(10) , Salary number(5), DepartmentId number(5) );
Department 表包含公司全部部門的信息。oracle
create table Department ( Id number(5), Name varchar2(10) );
插入數據Employee,腳本以下函數
insert into Employee (ID, NAME, SALARY, DEPARTMENTID) values ('1', 'Joe', '85000', '1'); insert into Employee (ID, NAME, SALARY, DEPARTMENTID) values ('2', 'Henry', '80000', '2'); insert into Employee (ID, NAME, SALARY, DEPARTMENTID) values ('3', 'Sam', '60000', null); insert into Employee (ID, NAME, SALARY, DEPARTMENTID) values ('4', 'Max', '90000', '1'); insert into Employee (ID, NAME, SALARY, DEPARTMENTID) values ('5', 'Janet', '69000', '1'); insert into Employee (ID, NAME, SALARY, DEPARTMENTID) values ('6', 'Randy', '85000', '1'); insert into Employee (ID, NAME, SALARY, DEPARTMENTID) values ('7', 'Will', '70000', '1'); insert into Employee (ID, NAME, SALARY, DEPARTMENTID) values ('8', 'eda', '50000', '2'); insert into Employee (ID, NAME, SALARY, DEPARTMENTID) values ('9', 'eason', '40000', '2');
插入數據Department,腳本以下性能
insert into Department (ID, NAME) values ('1', 'IT'); insert into Department (ID, NAME) values ('2', 'Sales');
如下使用四種SQL語句查出的結果,前兩個是用oracle特有函數,後兩個是標準SQL92寫法。spa
你以爲哪一個對?哪一個性能高?code
select Department,Employee,Salary from (select (ROW_NUMBER() over(PARTITION by t1.departmentid order by Salary desc)) lev, t2.name Department, t1.name Employee, t1.Salary Salary from Employee t1, Department t2 where t1.departmentid = t2.id) A where lev <= 3;
select D.Name Department, E.Name Employee, E.Salary Salary from (select Name, Salary, DepartmentId, dense_rank() over(partition by DepartmentId order by Salary desc) Trank from Employee) E right join Department D on E.DepartmentId = D.id where Trank <= 3;
select d.name as Department, e.name as Employee, e.salary as Salary from employee e inner join department d on e.DepartmentId = d.id where (select count(distinct salary) from employee where salary > e.salary and departmentid = e.DepartmentId) < 3 order by e.departmentid, Salary desc;
SELECT t3.name Department, t2.name Employee, t2.salary Salary FROM Employee t2, Department t3 WHERE t2.id NOT IN (SELECT b.id FROM Employee a, Employee b WHERE a.DepartmentId = b.DepartmentId AND a.salary > b.salary GROUP BY b.id HAVING COUNT(*) >= 3) AND t2.DepartmentId = t3.id ORDER BY Department, t2.salary DESC;
感興趣的同窗能夠本身跑下。htm
我我的以爲所謂官方答案是有問題的。
官方題解以下,mysql版本:
SELECT d.Name AS 'Department', e1.Name AS 'Employee', e1.Salary FROM Employee e1 JOIN Department d ON e1.DepartmentId = d.Id WHERE 3 > (SELECT COUNT(DISTINCT e2.Salary) FROM Employee e2 WHERE e2.Salary > e1.Salary AND e1.DepartmentId = e2.DepartmentId);
改寫成oracle版,加上排序:
SELECT d.Name Department, e1.Name Employee, e1.Salary FROM Employee e1 JOIN Department d ON e1.DepartmentId = d.Id WHERE 3 > (SELECT COUNT(DISTINCT e2.Salary) FROM Employee e2 WHERE e2.Salary > e1.Salary AND e1.DepartmentId = e2.DepartmentId) order by d.id,salary desc
查出來的數據是與通用寫法1同樣的, 兩個一樣的85000的數據
|序號| Department | Employee | Salary | |--- | ---- | ------- | ------------ | |1 | IT | Max | 90000 |2 | IT | Randy | 85000 |3 | IT | Joe | 85000 |4 | IT | Will | 70000 |5 | Sales | Henry | 80000 |6 | Sales | Sam | 60000 |7 | Sales | eda| 50000
這個題目出的歧義太大,若是是在考試中,應該是查出前三名、前四名的都對。
我的認爲應該查出前三名應該是不包含70000這條數據的,就算是並列第二,那麼就應該沒有第三了,高校排名不也是這樣嗎?
因此私覺得正確答案應該是查出這樣的數據
|序號| Department | Employee | Salary | |--- | ---- | ------- | ------------ | |1 | IT | Max | 90000 |2 | IT | Randy | 85000 |3 | IT | Joe | 85000 |4 | Sales | Henry | 80000 |5 | Sales | Sam | 60000 |6 | Sales | eda| 50000
那麼,我寫的四條語句中,應該是函數1及通用寫法2能夠知足這個條件。
個人公衆號
原文出處:https://www.cnblogs.com/yaomaomao/p/11133437.html