Codeforces Round #651 (Div. 2) 部分題解

A - Maximum GCD /*Keep on going Never give up*/ #pragma GCC optimize(3,"Ofast","inline") #include <bits/stdc++.h> const int maxn = 1e6+10; const int MaxN = 0x3f3f3f3f; const int MinN = 0xc0c0c00c; typ

>>阅读原文<<