題目地址:https://pintia.cn/problem-sets/994805260223102976/problems/994805311146147840ios
給定一系列正整數,請按要求對數字進行分類,並輸出如下 5 個數字:測試
每一個輸入包含 1 個測試用例。每一個測試用例先給出一個不超過 1000 的正整數 N,隨後給出 N 個不超過 1000 的待分類的正整數。數字間以空格分隔。spa
對給定的 N 個正整數,按題目要求計算 A1~A5 並在一行中順序輸出。數字間以空格分隔,但行末不得有多餘空格。code
若其中某一類數字不存在,則在相應位置輸出 N
。ip
13 1 2 3 4 5 6 7 8 9 10 20 16 18
30 11 2 9.7 9
8 1 2 4 5 6 7 9 16
N 11 2 N 9
理解好題意便可。數據對5取餘運算,分類處理。ci
#include <stdlib.h> #include <iomanip> #include <iostream> using namespace std; int main() { int T; cin >> T; int sample[T]; for (int i = 0; i < T; ++i) { cin >> sample[i]; } int A1 = 0, A2 = 0, A3 = 0, A4 = 0, A5 = -1; // 控制 A2的交錯求和 int flagA2 = 1; // 標誌A2 是否進行了計算 int isSumA2 = false; // 標誌A4的個數,以便於後面計算平均數 int counterA4 = 0; for (int j = 0; j < T; ++j) { int element = sample[j]; int remainder = element % 5; switch (remainder) { case 0: if (element % 2 == 0) { A1 += element; } break; case 1: if (flagA2) { A2 += element; flagA2 = !flagA2; isSumA2 = true; } else { A2 -= element; flagA2 = !flagA2; isSumA2 = true; } break; case 2: A3++; break; case 3: A4 += element; counterA4++; break; case 4: if (A5 < element) { A5 = element; } break; default: break; } } if (A1 != 0) { cout << A1 << " "; } else { cout << "N "; } if (isSumA2) { cout << A2 << " "; } else { cout << "N "; } if (A3) { cout << A3 << " "; } else { cout << "N "; } if (A4) { float result = (float)A4 / (float)counterA4; cout << setiosflags(ios::fixed) << setprecision(1) << result << " "; } else { cout << "N "; } if (A5 > -1) { cout << A5 << endl; } else { cout << "N" << endl; } return 0; }