如今有兩個數組 arr1 和 arr2數組
let arr1 = [1,2,3,4,4]
let arr2 = [3,4,5,6,7]
1.數組的並集:spa
let union = new Set([...arr1,...arr2])
2.數組的交集code
let intersect = new Set([...arr1].filter(item => arr2.has(item)))
3. 數組的差集blog
let difference = new Set([...arr1].filter(item => !arr2.has(item)))